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The molecular mass of a compound is equivalent to the sum of the atomic masses of each element present in that compound.

In\({\rm{HC}} \equiv {\rm{CH}}\), there are 2 carbon and 2 hydrogen atoms, and the atomic mass of 1 carbon and 1 hydrogen atoms are 12 amu and 1 amu, respectively. Therefore, the molecular mass of the compound will be \({\rm{12 }} \times {\rm{ 2 + 1 }} \times {\rm{ 2 = 26 amu}}\)

The molecular mass of a compound is equivalent to the sum of the atomic mass of each element present in that compound.

In\({{\rm{C}}_2}{{\rm{H}}_4}\), there are 4 hydrogen and 2 carbon atoms, and the atomic masses of 1 hydrogen and 1 carbon atom are 1 amu and 12 amu, respectively. Therefore, the molecular mass of the compound will be \({\rm{1 }} \times {\rm{ 4 + 12 }} \times {\rm{ 2 = 28 amu}}\)

The molecular mass of a compound is equivalent to the sum of the atomic mass of each element present in that compound.

In \({{\rm{C}}_2}{{\rm{H}}_6}\), there are 2 carbon and 6 hydrogen atoms, and the atomic mass of 1 carbon and 1 hydrogen atom is12 amu and 1 amu, respectively. Therefore, the molecular mass of the compound will be \({\rm{12 }} \times {\rm{ 2 + 1 }} \times {\rm{ 6 = 30 amu}}\).