91Ó°ÊÓ

An inch is used inimperialand US customary unit systems, while a centimeter is used in aninternationalunit system. They both are a measure of length and height.

Here we define that

\(1\,\,{\rm{inch}}\,\, = \,\,2.54\,\,{\rm{centimeters}}\)

\(1\,\,{\rm{centimeter}} = 0.393701\,\,{\rm{inch}}\,\,\)

One foot is twelve times an inch which is used in regular life.

The given distance between the centers of the two oxygen atoms of the oxygen molecule is 1.21 10^-8 cm.

For the conversion,

\(1\,\,{\rm{inch}}\,\, = \,\,2.54\,\,{\rm{centimeters}}\)

Hence,

\(\begin{array}{c}1.21\, \times \,{10^{ - 8}}\,{\rm{centimeters}}\,\,\\ = \,\,1.21\, \times \,{10^{ - 8}}\left( {\,{\rm{centimeters}}\, \times \,\frac{{{\rm{inch}}}}{{2.54\,\,{\rm{centimeters}}}}} \right)\,\,\\ = \,\,\frac{{1.21\, \times \,{{10}^{ - 8}}}}{{2.54}}\,\,{\rm{inch}}\,\,\\ = \,\,0.4764\, \times \,{10^{ - 8}}\,{\rm{inch}}\,\,\\ \approx \,\,4.764\, \times \,{10^{ - 9}}\,{\rm{inch}}\end{array}\)

Therefore, the distance between the centers of the two oxygen atoms in the oxygen molecule in inches is4.76 10^-9 inches (rounding off to 3 significant figures).