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How do the concentrations of \(P{b^{2 + }}\) \(and {S^{2 - }}\) change when \({K_2}\;S\) is added to a saturated solution of PbS?

Short Answer

Expert verified

The concentration of \(\left[ {P{b^{2 + }}} \right] \;\)decreases, while\(\;\left[ {{S^{2 - }}} \right] \) decreases.

Step by step solution

01

To find the concentrations of \(\;Pb{\;^{2 + }}\)  \(and {S^{2 - }}\)   change when  \({K_2}\;S\)    is added to a saturated solution of PbS

The equilibrium will shift towards forming more PbS. Adding\({K_2}S\) will increase

\(\left[ {{S^{2 - }}} \right]\) , therefore, the system will react by trying to minimize the stress (Le Chatelier's Principle).

02

STEP-2: Applying  Le Chatelier’s  principle:

Le Chatelier’s principle explains that if equilibrium is disturbed by variations of conditions ,equilibrium position is shifted to balance change in order to reestablish the equilibrium,hence the equilibrium is shifted towards forming more PbS, and thus addition of K2S would increase concentration of\(\left[ {{S^{2 - }}} \right]\).

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