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Chapter 3: Q77 E (page 172)

Copper(I)iodide (Cu I), is often added to table salt as a dietary source of iodine. How many moles of Cu I are contained in 1.00 lb (454g) of table salt containing 0.0100% Cu I by mass?

Short Answer

Expert verified

0.238 millimoles of Cu I are contained in 1.00 lb (454g) of table salt containing 0.0100% Cu I by mass.

Step by step solution

01

Step 1- Given data

Mass of table salt= 1.00lb = 454g

Copper(I)iodide present in the table salt= 0.0100% by mass

02

Step 2- Calculating millimoles

Copper(I)iodide present in 1 pound of salt= 0.001% of 454g

= 0.0454g

Molar mass of CuI= 63.54g + 126.90g= 190.44g

Moles=Mass/Molar mass

= 0.0454/190.44

=2.38 x 10-4 moles or 0.238 millimoles.

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