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Chapter 3: Q3.18 CYL (page 153)

What volume of a 1.50-MKBr solution contains 66.0 g KBr?

Short Answer

Expert verified

0.370 L of a 1.50-MKBr solution contains 66.0 g KBr

Step by step solution

01

Determine the moles of KBr present

Molarity of KBr = 1.50 M

Mass = 66 g

Molecular weight of KBr = 39 + 80 = 119 g/mol

Moles of KBr = 66 g/ 119 g/mol = 0.554 mole

02

Determine the volume of the solution

Molarity = Moles / Liters of solution

Plugging respective values in the above eq

1.50 M= 0.554 mole / Liter of solution

Liters of solution = 0.554/ 1.50 = 0.3693 L = 0.370 L

Therefore, 0.370 L of a 1.50-MKBr solution contains 66.0 g KBr

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