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Chapter 3: Q 43E (page 170)

Question-A major textile dye manufacturer developed a new yellow dye. The dye has a percent composition of 75.95% C, 17.72%N, and 6.33% H by mass with a molar mass of about 240g/mol. Determine the molecular formula of the dye.

Short Answer

Expert verified

The molecular formula of dye is C15N3H15.

Step by step solution

01

Step 1- Given data

Percent composition of C = 75.95%

Percent composition of N = 17.72%

Percent composition of H = 6.33%

02

Step 2- Calculating moles

The molar mass of carbon = 12g

The molar mass of nitrogen = 14g

The molar mass of hydrogen = 1g

Moles = given mass/molar mass

Moles of Carbon = 75.95/12 = 6.33mol

Moles of hydrogen = 6.33/1 = 6.33mol

Moles of nitrogen = 17.72/14 = 1.27mol

Simplest ratio;

Moles of carbon = 6.33/1.27 = 4.98mol = 5mol

Moles of hydrogen = 6.33/1.27 = 4.98mol = 5mol

Moles of nitrogen = 1.27/1.27= 1mol

Therefore, the empirical formula = C5NH5

03

Step 3- Calculating molecular formula

Empirical formula mass = 12x5+14+1x5 = 79g

n = molar mass/empirical formula mass

= 240/79= 3.04 = 3

Molecular formula = empirical formula x 3

Molecular formula= C15N3H15

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