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Explain why the neutralization reaction of a weak acid and a strong base gives a weakly basic solution

Short Answer

Expert verified

Reaction of hydrolysis of conjugated base from the weak acid produces \(O{H^ - }\)makes the solution basic

Step by step solution

01

Define weak acid and a strong base:

When weak acids react with strong bases, the weak acid's \({H^ + }\) is transferred to the strong base's \(O{H^ - }\), resulting in the formation of water and a salt. The resulting salt, on the other hand, will almost certainly be soluble and should be stated as ions.

02

Reaction of a weak acid and a strong base:

Ionization of a weak acid as

\(\begin{aligned}{HA(aq) \to {H^ + }(aq) + {A^ - }(aq)}\\{}\end{aligned}\)

Ionization of a strong base as

\(BOH \to {B^ + }(aq) + O{H^ - }(aq)\)

Weak acid denotes that the equilibrium constant is on the acid molecule's side, meaning that it does not fully ionise while the strong base does. More \(O{H^ - }\)ions than \({H^ + }\)ions. Mixing the two solutions are \(O{H^ - }\)ions will react with \({H^ + }\)ions to form water. The final solution has a higher concentration of \(O{H^ - }\)ions have a solution basic. \(O{H^ - }\)ions form water with \({H^ + }\)ions neutralize has less basic as a base solution. Mixing of two solutions as a result for base formation \(BA\).If salt is soluble will dissolve in water into \({A^ - }and\;{B^ + }\)ions. \({A^ - }\)is a conjugated base of a weak acid it is a strong base.

\({A^ - }(aq) + {H_2}O(aq) \to HA(aq) + O{H^ - }(aq)\)

Forming an acid molecule an \(O{H^ - }\)ion. Hydroxide ions to add the acidity of the solution by mixing the two solutions.

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Most popular questions from this chapter

What is the effect on the concentrations of \(N{O_2}^ - ,HN{O_2},\)and \(O{H^ - }\)when the following are added to a solution of \(KN{O_2}\)in water?

\(\begin{aligned}{l}(a)HCl\\(b)HN{O_2}\\(c)NaOH\\(d)NaCl\\(e)KNO\end{aligned}\)

The equation for the equilibrium is \(NO_2^ - (aq) + {H_2}O(l) \rightleftharpoons HN{O_2}(aq) + O{H^ - }(aq)\)

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