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Chapter 4: Q66P (page 180)

Give the oxidation number of nitrogen in the following:

(a)NH2OH(b)N2F4(c)NH4+(d)HNO

Short Answer

Expert verified

Answer: You need to provide the oxidation no of nitrogen for the given compounds


Step by step solution

01

Oxidation state of nitrogen in NH2OH 

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in NH2OH is x.

No you can write,

x+2+1+-2++1=0x=-1

Hence, oxidation state of nitrogen in NH2OH is -1.

02

Oxidation state of nitrogen in N2F4 

Oxidation state of Flurine is -1.

Let, oxidation state of nitrogen in N2F4 is y.

No you can write,

2y+4-1=02y=+4y=+2

Hence, oxidation state of nitrogen in N2F4 is +2.

03

Oxidation state of nitrogen in NH3+ 

Oxidation state of Hydrogen is +1.

Let, oxidation state of nitrogen in NH3+is z.

No you can write,

z+4+1=+1z=-3

Hence, oxidation state of nitrogen in NH3+is -3.

04

Oxidation state of nitrogen in HNO2 

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in HNO2is k.

No you can write,

+1+k+2-2=0k=+3

Hence, oxidation state of nitrogen in HNO2is +3.

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