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Chapter 4: Q4.140CP (page 185)

Question: The amount of ascorbic acid (vitamin C; C₆H₈O₆) in tablets is determined by reaction with bromine and then titration of the hydrobromic acid with standard base:
$C_{6} H_{8} O_{6} + B r_{2} 鈫� C_{6} H_{6} O_{6} + 2 H B r H B r + N a O H 鈫� N a B r + H_{2} O$
A certain tablet is advertised as containing 500 mg of vitamin C. One tablet was dissolved in water and reacted with Br₂. The solution was then titrated with 43.20 mL of 0.1350 MNaOH. Did the tablet contain the advertised quantity of vitamin C?

Short Answer

Expert verified

Answer: Yes, the tablet contains the advertised quantity of vitamin C.

Step by step solution

01

Overall reaction

The given reactions are,

$C_{6} H_{8} O_{6} + B r_{2} 鈫� C_{6} H_{6} O_{6} + 2 H B r H B r + N a O H 鈫� N a B r + H_{2} O$

The overall reaction for above reactions is,

$C_{6} H_{8} O_{6} + B r_{2} 鈫� C_{6} H_{6} O_{6} + 2 H B r H B r + N a O H 鈫� N a B r + H_{2} O_________________________________________C_{6} H_{8} O_{6} + B r_{2} + N a O H 鈫� C_{6} H_{6} O_{6} + H B r + N a B r + H_{2} O$

So, the overall reaction is, $C_{6} H_{8} O_{6} + B r_{2} + N a O H 鈫� C_{6} H_{6} O_{6} + H B r + N a B r + H_{2} O$

02

Step 2: Determination of quantity of vitamin C

The number of moles of NaOH are,

$M o l e s = c o n c e n t r a t i o n 脳 v o l u m e = 0.1350 M 脳 0.0432 L = 0.00583 m o l$

From equation (1), 1 mol of C₆H₈O₆ produces 2 moles of HBr.

So, moles of C₆H₈O₆ are,

$\frac{1}{2} 脳 0.00583 m o l = 0.002916 m o l$

The mass of C₆H₆O₆ is,0.002916 mol

Thus, it is concluded that the tablet contains the advertised quantity of vitamin C.

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Most popular questions from this chapter

Question: In a car engine, gasoline (represented by C8H18) does not burn completely, and some CO, a toxic pollutant, forms along with CO2 and H2O. If 5.0% of the gasoline forms CO:

(a) What is the ratio of CO₂ to CO molecules in the exhaust?

(b) What is the mass ratio of CO₂ to CO?

(c) What percentage of the gasoline must form CO for the mass ratio of CO₂ to CO to be exactly 1/1?

Question: State a general equation for a neutralization reaction.

The brewing industry uses yeast microorganisms to convert glucose to ethanol for wine and beer. The baking industry uses the carbon dioxide produced to make bread rise:

$C_{6} H_{12} O_{6} (s) \overset{yeast}{鈫�} 2 C_{2} H_{5} OH (l) + 2 {CO}_{2} (g)$

How many grams of ethanol can be produced from 100g of glucose? What volume of CO₂ is produced? (Assume 1 mol of gas occupies 22.4 L at the conditions used.)

Physicians who specialize in sports medicine routinely treat athletes and dancers. Ethyl chloride, a local anesthetic commonly used for simple injuries, is the product of the combination of ethylene with hydrogen chloride:

$C_{2} H_{4} (g) + HCI (g) 鈫� C_{2} H_{5} CI (g)$

If 0.100 kg of C2H4 and 0.100 kg of HCl react:

(a) How many molecules of gas (reactants plus products) are present when the reaction is complete?

(b) How many moles of gas are present when half the product forms?

Ammonia is produced by the millions of tons annually for use as a fertilizer. It is commonly made from N₂ and H₂ by the Haber process. Because the reaction reaches equilibrium before going completely to product, the stoichiometric amount of ammonia is not obtained. At a particular temperature and pressure, 10.0 g of H₂ reacts with 20.0 g of N₂ to form ammonia. When equilibrium is reached, 15.0 g of NH₃ has formed.

(a) Calculate the percent yield.

(b) How many moles of N₂ and H₂ are present at equilibrium?

See all solutions

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