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A student forgets to weigh a mixture of sodium bromide dehydrate and magnesium bromide hexahydrate. Upon strong heating, the sample loses 252.1 mg of water. The mixture of anhydrous salts reacts with excess AgNO3 solution to form 6.00x10-3 mol of solid AgBr. Find the mass % of each compound in the original mixture.

Short Answer

Expert verified

The mass % of NaBr.2H2Oand MgBr2.6H2O are 32.22% and 67.78%, respectively.

Step by step solution

01

Mass of water lost

Sodium bromide dehydrate on strong heating loses 2 moles of water

NaBr.2H2ONaBr.2H2O

Molar mass of NaBr.2H2O = 138.922 g/mol

Molar mass of H2O = 18.016 g/mol.

So, 138.922 g of NaBr.2H2O loses 36.032 g of water.

Similarly, Magnesium bromide dehydrate on strong heating loses 6 moles of water

MgBr2.6H2OMgBr2+6H2O

Molar mass of MgBr2.6H2O = 292.206 g/mol

Molar mass of H2O = 18.016 g/mol.

So, 138.922 g of MgBr2.6H2O loses 108.096 g of water.

Total mass of the mixture is,

138922g+292.206g=431.128g

Total mass of water lost is,

36.02g+108.096g=144.128g

Actual mass of water lost = 252.1 mg = 0.2521 g

Mass of the mixture that loses 0.2521 g is,

0.2521gH2O431.128g144.128g=0.7541g

02

Determination of mass%

Mass of NaBr.2H2O present in 0.7541 g mixture is,

=0.7541g138.922g431.128gmixture=0.2430g

Mass percent of NaBr.2H2O is,

=masstotalmass100%=0.2430g0.7541g100%=32.22%

Mass percent of MgBr2.6H2O is,

=100%-32.22%

=67.78%

Hence, the mass % of NaBr.2H2Oand MgBr2.6H2O are 32.22% and 67.78%, respectively.

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