/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 4.8 P Why are some covalent compounds ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Why are some covalent compounds soluble in water and others are not?

Short Answer

Expert verified

The covalent compounds which do not contain any polar bonds are insoluble in water. Covalent compounds which contain polar bonds are soluble in water.

Step by step solution

01

Define the Covalent compounds

Covalent compounds are formed by covalent bonding between two or more atoms.A covalent bond between two atoms is formed by the equal sharing of electrons from both atoms. The pair of electrons which participates in bonding is called a shared pair or bonding pair. The sharing of electrons can be done between the same kind of atoms or between different kinds of atoms.

02

Determine the solubility of covalent compounds in water

Covalent compounds do not dissociate into ions as ionic compound does but some covalent compound contain polar bonds in their molecules due to which they become soluble in water like sugar, alcohol, etc. butmost of the covalent compounds which do not contain any polar bonds are insoluble in water like benzene, octane, etc.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe what happens on the molecular level when acetic acid dissolves in water.

Balance each of the following redox reactions and classify it as a combination, decomposition, or displacement reaction:

(a)Mg(s)+H2O(g)→Mg(OH)2(s)+H2(g)

(b)Cr(NO3)3(aq)+Al(s)→Al(NO3)3(aq)+Cr(s)

(c)PF3(g)+F2(g)→PF5(g)

Question: In a car engine, gasoline (represented by C8H18) does not burn completely, and some CO, a toxic pollutant, forms along with CO2 and H2O. If 5.0% of the gasoline forms CO:

(a) What is the ratio of CO2 to CO molecules in the exhaust?

(b) What is the mass ratio of CO2 to CO?

(c) What percentage of the gasoline must form CO for the mass ratio of CO2 to CO to be exactly 1/1?

Question: Over time, as their free fatty acid (FFA) content increases, edible fats and oils become rancid. To measure rancidity, the fat or oil is dissolved in ethanol, and any FFA present is titrated with KOH dissolved in ethanol. In a series of tests on olive oil, a stock solution of 0.050 M ethanolic KOH was prepared at 250C , stored at 0oC, and then placed in a 100-mL buret to titrate any oleic acid CH3CH27CH=CHCH27COOHpresent in the oil. Each of four 10.00-g samples of oil took several minutes to titrate: the first required 19.60 mL, the second 19.80 mL, and the third and fourth 20.00 mL of the ethanolic KOH.

(a) What is the apparent acidity of each sample, in terms of mass % of oleic acid? (Note: As the ethanolic KOH warms in the buret, its volume increases by a factor of .)

(b) Is the variation in acidity a random or systematic error? Explain.

(c) What is the actual acidity? How would you demonstrate this?

The net ionic equation for the aqueous neutralization reaction between acetic acid and sodium hydroxide is different from that for the reaction between hydrochloric acid and sodium hydroxide. Explain by writing balanced net ionic equations.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.