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Why is∆Svapof a substance always larger than ∆Sfus.

Short Answer

Expert verified

The energy gain from heat and the volume expansion, which is characteristic of entropy rise, characterise vaporisation. Fusion, on the other hand, entails volume contraction: when the substance solidifies, the entire volume shrinks.

As a result, the vaporisation entropy exceeds the fusion entropy

Step by step solution

01

Concept Introduction

The mechanism through which the state of a liquid converts into the condition of a vapour is known as vaporisation. As the temperature rises, the kinetic energy of the molecules rises as well.

When two light atoms combine to form a heavier one, this is called fusion. The new atom's total mass is less than the two that generated it; the "missing" mass is released as energy.

02

Equations for vaporization and fusion

Upon vaporization, the substance changes its physical state from liquid to gas, for example water –

H2O(l)→H2O(g)

The entropy of vaporization can be represented as –

∆Svaporization=Sgas-Sliquid

Similarly, upon fusion the substance changes its physical state from liquid to solid, for example water –

H2O(l)→H2O(s)

The entropy of fusion can be represented as –

∆Sfusion=Sliquid-Ssolid

03

Entropy of vaporization is greater than fusion

The difference in entropy is –

∆S=∆Svaporization-∆Sfusion=(Sgas-Sliquid) - (Sliquid-Ssolid)=Sgas+Ssolid

The vaporization is characterized by the energy gain from heat and the volume expansion, characteristic to entropy increase. Whereas fusion involves volume contraction - as the substance is solidified, so the total volume is reduced.

Therefore, the vaporization entropy is larger than the fusion entropy.

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