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Chapter 11: Q10P (page 433)

What is the hybridization of bromine in each of the following: (a) BrF2 ; (b) BrO2 ; (c) BrF5 ?

Short Answer

Expert verified

The hybridization of bromine is given by

H=GA+(VE-V-C)2

Where H-hybridization of a central atom

GA- number of groups attached to a central atom

VE-valence electrons of a central atom

V-valency of a central atom

C-charge on molecule

Step by step solution

01

hybridization of bromine in BrF3

GA=3, VE=7, V=3, C=0

By substituting the value in the equation

H=GA+(VE-V-C)2=3+[7-3-(0)]2=5(sp3d)

H = Hence, the hybridization of chlorine in BeF3is sp3d

02

hybridization of bromine in BrO2 

GA=2, VE=7, V=4, C=-1

By substituting the value in equation

H=GA+(VE-V-C)2=2+[7-4-(-1)]2=4(sp3)

Hence, the hybridization of chlorine in BrO2is sp3

03

Hybridization of bromine in BrF5 

GA=5, VE=7, V=5, C=0

By substituting the value in equation

H=GA+(VE-V-C)2=5+[7-5-(0)]2=5(sp3d2)

Hence, the hybridization of bromine in BrF5is sp3D2

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Most popular questions from this chapter

Isoniazid (below) is an antibacterial agent that is very useful against many common strains of tuberculosis.

  1. How many sigma bonds are in the molecule?
  2. What is the hybridization of each C and N atom?

Which types of atomic orbitals of the central atom mix to form hybrid orbitals in

(a) SiCIH3 ; (b) CS2 ; (c) SCI3F ; (d) NF3 ?

Use partial orbital diagrams to show how the atomic orbitals of the central atom lead to the hybrid orbitals in:

a.IF2-b.ICI3c.XeOF4d.BHF2

How many hybrid orbitals form when four atomic orbitals of a central atom mix? Explain

Use partial orbital diagrams to show how the atomic orbitals of the central atom lead to hybrid orbitals in

(a) GeCl4

(b) BCl3

(c) CH3+
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