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Calculate the molality, molarity, and mole fraction of NH3 in an 8.00 mass % aqueous solution (d = 0.9651 g/mL)?

Short Answer

Expert verified

The number of moles of NH3and water is 0.471mole and 5.1mole. The molality and mole fraction and molarity of NH3is 5.12m, 0.085 and 4.55M respectively.

Step by step solution

01

Concentration of the Solution

Solution can be formed from the dissolution of the solute in the solvent.The solute decides the nature of the solution.

Molality can be defined as the ratio of the mass of the solute to the mass of the solution present in kilogram measure.

Molality=Number of MolesMass of the Solution ( in kilogram )

Molarity can be defined as the ratio of the mass of the solute to the volume of the solution present in litre measure.

Molarity=Number of MolesVolume of the Solution ( in Litre )

Number of moles can be defined as the ratio of the mass of the atom/molecule and molar mass of the atom/molecule.

Number of Moles=MassMolar Mass

Mole Fraction can be defined as the ratio of the number of moles of the solute to the number of moles of solvent and number of solute.

Mole Fraction=Number of Moles of One ComponentNumber of Moles of the Solvent+Number of Moles of Solute

Parts by mass: It can be defined as the percentage of the ratio of the mass of solute to the total mass of the solution.

Parts by Mass=Mass of SoluteMass of the Solution×100

Density can be defined as the ratio of the mass of the matter to the volume of the matter.

Density=MassVolume

02

Expression to calculate the Concentration

8% mass ofNH3means that 8g ofNH3 present in the 100g of solution.

Now,

role="math" localid="1659358958091" Massofsolution=Massofsolvent,water+MassofsoluteMassofSolvent,water=Massofsolution-Massofsolute,NH3MassofSolvent,water=100g-8gMassofSolvent,water=92g

Mass of Solute,massNH3=8g

Molar Mass of Solute, MNH3=17g/mol

Number of Moles=MassMolar MassNumberofMoles of NH3=8g17g/molNumberofMoles of NH3=0.471mol

Mass of Solvent, Water Masssolvent=92g=0.092kg

role="math" localid="1659359118224" Number of Moles=MassMolar MassNumberofMoles of Water=92g18g/molNumberofMoles of Water=5.1mol

Number of moles of solute, NH3=0.471mol

Number of moles of solvent, Water nwater=5.1 mol


Mole Fraction=Number of Moles of One ComponentNumber of Moles of the Solvent+Number of Moles of SoluteMole Fraction of NH3=0.4715.1+0.471Mole Fraction of NH3=0.4715.571Mole Fraction of NH3=0.085

Number of moles of NH3=0.471mol

Molality=Number of MolesMass of the Solution ( in kilogram )Molality=0.471mole0.092kgMolality=5.12m

Density of the Solution d=0.9651g/mL

Density of Solution=MassVolume0.9651g/mL=100gVolumeVolume=100g0.9651g/mLVolume=103.62mL

Volume of solution Volume of solution=103.62mL=0.10362L

Molarity=Number of Moles of soluteVolume of the Solution ( in Litre )=0.471mol0.10362L=4.55M

The molarity of NH3=4.55M

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