Q13.7 P Which gives the more concentrate... [FREE SOLUTION]

Chapter 13: Q13.7 P (page 546)

Which gives the more concentrated solution,
(a) ${KNO}_{3}$ In $H_{2} O$ or
(b) ${KNO}_{3}$ in carbon tetrachloride $({CCl}_{4})$ ? Explain.

Short Answer

Expert verified

${KNO}_{3}$ In $H_{2} O$ will give a more concentrated solution than ${KNO}_{3}$ in carbon tetrachloride.

Step by step solution

Check the polarity of both solvent and solute

A more concentrated solution means more solute has been dissolved in the solvent. And basic rule behind dissolution is like dissolution like which means a polar solute will be dissolved in a polar solvent and vice versa.

${KNO}_{3}$ is an ionic salt, which means it is polar in nature Carbon tetrachloride is nonpolar in nature and water is polar in nature.

More solubility, more concentrated the solution

${KNO}_{3}$ being a polar compound will dissolve more in polar solvent i.e., water. Potassium nitrite is not soluble in non-polar carbon tetrachloride. Because ${KNO}_{3}$ dissolves to a greater degree in water, it will form a more concentrated solution.

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91影视

Which gives the more concentrated solution,
(a) ${KNO}_{3}$ In $H_{2} O$ or
(b) ${KNO}_{3}$ in carbon tetrachloride $({CCl}_{4})$ ? Explain.

Short Answer

Step by step solution

Check the polarity of both solvent and solute

More solubility, more concentrated the solution

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91影视

Which gives the more concentrated solution,(a)KNO3InH2Oor (b) KNO3in carbon tetrachloride CCl4? Explain.

Short Answer

Step by step solution

Check the polarity of both solvent and solute

More solubility, more concentrated the solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Making Measurements

Chemical Analysis

Kinetics

Inorganic Chemistry

The Earths Atmosphere

Chemistry Branches

Study anywhere. Anytime. Across all devices.

Which gives the more concentrated solution,
(a) ${KNO}_{3}$ In $H_{2} O$ or
(b) ${KNO}_{3}$ in carbon tetrachloride $({CCl}_{4})$ ? Explain.