Q98P What is the freezing point of 0.... [FREE SOLUTION]

Chapter 13: Q98P (page 562)

What is the freezing point of 0.251 m urea in water?

Short Answer

Expert verified

The freezing point is $- 0 . 664^{掳} C$

Step by step solution

Concept

The freezing point of a solution containing a non-volatile solute is lower than the freezing point of a pure solvent. The depression in the freezing point can be calculated as:

${螖罢}_{f} = {iK}_{f} m$

where the $K_{f}$ is the molal freezing point depression constant and its value is equal to $1.86 {}^{掳}C / m$ for aqueous solutions. The mis the molality of the particles, the iis the van鈥檛 Hoff factor, and its value for 1 urea is 1 because a urea is a non-electrolyte substance and it does not dissociate into ions in a solution

Calculate the depression in freezing point for urea (ΔTf)

$鈭� T_{f} = i K_{f} m = 1 . 86^{掳} C / m 脳 0.251 m = 0 . 466^{掳} C$

Freezing point of solution

${螖罢}_{f} = T_{solvent} - T_{solution} T_{solvent} = 0 掳 C 0 掳 C - T_{solution} = 0.466 掳 C T_{solution} = - 0.466 掳 C .$

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91影视

What is the freezing point of 0.251 m urea in water?

Short Answer

Step by step solution

Concept

Calculate the depression in freezing point for urea (ΔTf)

Freezing point of solution

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