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The freezing point of benzene is 5.5oC. What is the freezing point of a solution of 5.00 g of naphthalene (C10H8) in 444 g of benzene (of benzene = 4.90oC/m)?

Short Answer

Expert verified

The freezing point of the given solution is 5.07oc.

Step by step solution

01

Definition

The temperature at which the vapor pressure of a solution is equal to that of a pure solventis known as the freezing point of a solution.

Concept: For finding the freezing point we will use the equations below.

Tf=kfmTf-thefreezingpointofdepressionkf-themoladropofthefreezingpointconstantm-isthesolutionmolality

02

Further solution

Given information:

The freezing point of benzene=5.5C

The naphthalene in solution's mass = 5.00g

mass of the solvent of benzene = 444g

= 0.44 kg

kffor benzene=4.90C/m

Molality(m)ofthesolution=molesofsolute(mol)massofsolvent(kg)Molesofsolute=massofsolutemolarmassofsolutem=0.039.444=0.087molkg.

m=0.039.444=0.087molkg螖罢f=kfm=4.900.087=0.426=0.43oc.螖罢f=Tf(solvent)+Tf(solution)Tf(solution)=Tf(solvent)-Tf=5.5-0.43=5.07oc.

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