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Chapter 2: Q4.69P (page 40)

Give the oxidation number of phosphorus in the following:

aH2P2O72-bPH4+cPCl5

Short Answer

Expert verified

You need to provide the oxidation no of phosphorus for the given compounds.

Step by step solution

01

Oxidation state of phosphorus in H2P2O72-

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of phosphorus in H2P2O72-is x.

No you can write,

2+1+2x+7-2=-22x=+10x=+5

Hence, oxidation state of phosphorus in H2P2O72-is +5.

02

Oxidation state of phosphorus in PH4+

Oxidation state of Hydrogen is +1.

Let, oxidation state of phosphorus in PH4+is y.

No you can write,

y+4+1=+1y=-3

Hence, oxidation state of phosphorus in PH4+is -3.

03

Oxidation state of phosphorus in PCl5

Oxidation state of Chlorine is -1.

Let, oxidation state of phosphorus in PCl5is z.

No you can write,

z+5-1=0z=+5

Hence, oxidation state of phosphorus in PCl5is +5.

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