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Chapter 3: Q87P (page 134)

Cyanogen, (CN)2 has been observed in the atmosphere of Titan, Saturn鈥檚 largest moon, and in the gases of interstellar nebulas. On Earth, it is used as a welding gas and a fumigant. In its reaction with fluorine gas, carbon tetrafluoride and nitrogen trifluoride gases are produced. What mass of carbon tetrafluoride forms when 60.0 g of each reactant is used?

Short Answer

Expert verified

Mass formed of CF4during the reaction is 39.6 g.

Step by step solution

01

Writing balanced equation

First of all, let us check the balanced equation to find the amount ofCF4

(CN)2(g)+7F2(g)鈫�2CF4(g)+2NF3(g)

From the equation we can say that 1 mole of(CN)2and 7 moles of fluorine gasreact to givetwomoles of CF4

02

Calculating Moles of reactants

Moles can be calculated as

Moleof(CN)2=Moleof(CN)2MolarMass=6092=0.65

MoleofF2=MoleofF2MolarMass=6038=1.58

From the balanced equation we can say thatF2is the limiting reagent hence controls the formation of products and,

7 moles ofF2gives moles ofCF4= 2 moles

So, 1.56 moles of F2 will give = 27脳1.58=0.45Mole

03

Determine mass of  CF4 formed 

The mass ofCF4formed is calculated as:

MassofCF4=Mole脳Molarmass=0.45脳88=39.6g

So, mass formed of CF4 during the reaction is 39.6 g.

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