91影视

The distance between 鈥渢wo crests鈥� is the wavelength of a wave.

Representation of wave

In mathematics, the Greek symbol lambda () is used to indicate wavelength.

A. Determine the $纬$-ray energy and wavelength required to convert the excited state.

We need to use this formula:

鈥�.. (i)

• $纬$= Wavelength
• h = Planck鈥檚 constant
• c = Speed of light
• E = Energy

The binding energies are generally represented in millions of electron volts, or mega-electron volts (MeV), for the derivation:

$$\begin{gathered} 1MeV={10}^{6}eV \\ =1.602x{10}^{-13}J \end{gathered}$$

$$\begin{gathered} Energy(纬-ray)=(4.816-4.773)MeV \\ =0.043MeV \end{gathered}$$

The known values are substituted.

$位=\frac{\left(6.626x{10}^{-34}J.s\right)\left(\left(2.99792x{10}^8\frac{m}{s}\right.\right)}{0.043MeV}脳\left(\frac{1MeV}{1.602脳{10}^{-13}}\right)$

Therefore, the gamma-ray energy is 0.043 MeV and wavelength $位=2.8836脳{10}^{-11}m$.

B. The energy of a particle that would convert ²³³U to excited state II,

$$\begin{gathered} Energy=4.816MeV-\left(0.043MeV-0.060MeV\right) \\ =4.713MeV \end{gathered}$$

Therefore,the energy of the particle =4.173 MeV.