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The isotope 21283Bihas a half-life of1.01 yr. What mass (in mg) of a2.00 -mg sample will remain after3.75脳103h ?

Short Answer

Expert verified

The amount of21283Bithat remains is1.49mg

Step by step solution

01

Radioactive decay

The radioactive decay follows the first order kinetics. The relation between the rate constant and the half-life of the reaction is as shown below:

k=0.693t1/2

02

Calculation

- The half-life of83212Biist1/2=1.01yr

- The initial amount of83212BiwasN0=2.00mg

We have to find the mass of 83212Biafter timet=3.75103h

First, let us convert the time elapsed from hours to years

t=3.75103h1d24h1yr365d=0.428yr

Now, let us calculate the decay constant of83212Bi

k=ln(2)t1/2=0.6931.01yr=0.686yr-1

Therefore, the amount of21283Bithat remains after time t is

lnNtN0=-ktlnNt2.00mg=-0.686yr-1脳0.428测谤=-0.2936

\Nt2.00mg=e-0.2936Nt2.00mg=0.7456Nt=1.49mg

Hence,the amount of21283Bithat remains is1.49鈥尘驳.

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