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Rank the members of each set of compounds in order of increasing the ionic character of their bonds. Use polar arrows to indicate the bond polarity of each:

(a) HBr, HCl, HI

(b) H2O, CH4 , HF

(c) SCI2 , PCI3 , SiCI4

Short Answer

Expert verified

The intermolecular force between the molecules are:

  1. HBr, HCl, HI: The ionic character decreases as the electronegativity decreases down the group in the halogen series. So, the order of the ionic character is: HI < HBr < HCl.
  2. H2O , CH4 ,HF: The order of the ionic character is: CH4 < H2O <HF
  3. SCI2 , PCI3 , SiCI4 :The order of the ionic character is: SiCI4 < SCI2 < PCI3.

Step by step solution

01

Intermolecular Forces

Intermolecular forces are the interaction which are formed by the attraction of the two having opposite charges (partial positive and partial negative charge). The opposite charge are formed by the presence of the electron-negative atom in the molecule. Due to the presence of an electron-negative atom, there is an induced partial positive charge is generated on the electron-positive charge (or less electron-negative charge) atom. There will be an attraction between the both oppositely charges to form a bond.

Dipole-dipole Interaction: These interactions are the attractive forces which present in the polar molecules. Polar molecules have permanent dipoleswhich are produced by the presence of the opposite charge of the atom.

Ion-dipole interaction: These interactions are present in the ion and polar molecules. These interactions are similar to the dipole-dipole interaction.

London dispersion interaction: It is the weak bond which is formed for the short period of time. The bond is formed between the polar and non-polar molecules due to the phenomena of induction.

02

Explanation

HBr, HCl, HI: In this molecule opens are involved with the electropositive H-atom. As we know, halogens are the most electronegative atom which tends to form a polar molecule and form an ionic bond. So, the order of the ionic character is: HI < HBr < HCl.

H2O , CH4 ,HF: In H2O molecule, there is the formation of the polar molecule due to the presence of electronegative O-atom with electropositive H-atom. In CH4, there are fewer electronegative atoms as their difference in electronegativity is less and hence forms a non-polar molecule with dispersion force. In HF, F-atom is the most electronegative atom forming a bond with the electropositive H-atom forming a polar bond. The order of the ionic character is: CH4< H2O<HF

SCI2 , PCI3, SiCI4 :In SCI2 molecule, There are electronegative Cl-atom belongs to halogen group form bond with S-atom forming dipole-dipole interaction. In PCI3, Cl-atom bonding with metal electropositive atom forming with dipole-dipole interaction. In SiCI4, electronegative Cl-atom bonded with less electronegative S-atom forming dipole-dipole interaction. Therefore, the order of the ionic character is: SiCI4< SCI2 < PCI3.

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Most popular questions from this chapter

The energy of the C-C bond is 347 kJ/mol, and that of the Cl-Cl bond is 243 kJ/mol. Which of the following values might you expect for the C-Cl bond energy? Explain.

(a) 590 kJ/mol (sum of the values given)

(b) 104 kJ/mol (difference of the values given)

(c) 295 kJ/mol (average of the values given)

(d) 339 kJ/mol (greater than the average of the values given)

Is the H-O bond in water nonpolar covalent, polar-covalent, or ionic? Define each term, and explain your choice.

carbon- carbon bonds form the 鈥渂ackbone鈥 of nearly every organic and biological molecule. The average bond energy of the C-C bond is 347kJ/mol. Calculate the frequency and wavelength of the least energetic photon that can break an average C-C bond. In what region of the electromagnetic spectrum is this radiation?

The average C-H bond energy in CH4 is 415kJ/mol. Use table 9.2(p. 353) and the following to calculate the average C-H bond energy in ethane(C2H6;C-C bond), in ethene (C2H4;C=C bond), and ethyne (C2H2;CC):

C2H6(g)+H2(g)2CH4(g)鈥勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌螖贬o=-65.07kJ/molC2H4(g)+2H2(g)2CH4(g)鈥勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌螖贬o=-202kJ/molC2H2(g)+3H2(g)2CH4(g)鈥勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌勨赌螖贬o=-376.74kJ/mol

Use Figure 9.20, p. 364, to indicate the polarity of each bond with partial charges

(a) Br-Cl

(b) F-Cl

(c) H-O

(d) Se-H

(e) As-H

(f) S-N.

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