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The phase diagram is the diagram which shows thechange in phase. It tells about the change into all phases – Solid, Liquid and Gaseous.

It represents all the phases and transition are shown by the lines and the area between lines show the whole phase of the molecule.

Molar Mass of =64g/mole

Boiling Point = $\mathbf{-}{\mathbf{10}}^o\mathbf{C}$

Melting Point = $\mathbf{-}{\mathbf{73}}^o\mathbf{C}$

$\begin{array}{l}\mathrm{Δ}{H}^{o}fus=8.619kJ/mole\\ ChangeJ/moletoJ/g\\ ⇒\mathrm{Δ}{H}^{o}fus=\frac{8.619kJ/mole×1mole}{64g×1000J/kJ}\\ ⇒\mathrm{Δ}{H}^{o}fus=134.5J/g\\ \mathrm{Δ}{H^o}_{vap}=25.73kJ/mole\\ ⇒\mathrm{Δ}{H^o}_{vap}=\frac{25.73kJ/mole×1mole}{64g×1000J/kJ}\\ ⇒\mathrm{Δ}{H^o}_{vap}=401.6J/g\end{array}$

Specific Heat Capacity of liquid,$\mathbf{Cliq}$=0.995kJ/mole

Specific Heat Capacity of Gas,$\mathbf{Cgas}$=0.622kJ/mole

Mass of ${\mathbf{SO}}_2$= 2.5kg = 2500g

$\begin{array}{l}Convert\text{ }2.5kg\text{ }Solid\text{ }SO2\text{ }to\text{ }liquid\text{ }SO2\\ Specific\text{ }Heat\text{ }Cpacity,q=m\text{ }\mathrm{Δ}{H}^{o}fus\\ ⇒q=\left(2500\text{ }g\right)×(134.5\text{ }J/g)\\ ⇒q=336250\text{ }J\end{array}$

$\begin{array}{l}Convert\text{ }2.5kg\text{ }liquid\text{ }SO2\text{ }from-{73}^{o}C\text{ }to-{10}^{o}C\\ Specific\text{ }Heat\text{ }Cpacity,q=mCliq\text{ }\mathrm{Δ}T\\ \mathrm{Δ}T=(-{10}^{o}C)-(-{73}^{o}C)={63}^{o}C\\ ⇒q=2500g×0.995×{63}^{o}C\\ ⇒q=156712.5\text{ }J\end{array}$

$\begin{array}{l}Convert\text{ }2.5kg\text{ }liquid\text{ }SO2\text{ }into\text{ }Vapours\text{ }from-{10}^{o}C\text{ }to-{10}^{o}C\\ Specific\text{ }Heat\text{ }Capacity,q=m\text{ }\mathrm{Δ}{H^o}_{vap}\\ ⇒q=2500\text{ }g×401.6\text{ }J/g\\ ⇒q=1004000J\end{array}$

$\begin{array}{l}Convert\text{ }2.5kg\text{ }Gaseous\text{ }SO2\text{ }from-{10}^{o}C\text{ }to\text{ }{60}^{o}C\\ Specific\text{ }Heat\text{ }Capacity,q=MCgas\text{ }\mathrm{Δ}T\\ \mathrm{Δ}T=\left({60}^{o}C\right)-(-{10}^{o}C)={70}^{o}C\\ ⇒q=2500g×0.622j/gk×{70}^{o}C\\ ⇒q=108850J\end{array}$

The total heat energy required to convert solid into vapours.

$\begin{array}{l}Total\text{ }Energy=(336250+156712.5+1004000+108850)\\ qTotal=1605812.5J\end{array}$