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Chapter 5: Q5.13P (page 227)

What is the pressure (in Pa) of the gas in the flask in Figure P5.13?

Short Answer

Expert verified

The pressure of the gas is 4.75脳10鈥�3鈥�Pa.

Step by step solution

01

Determination of the pressure 

The pressure of the gas is equal to the difference in height of the mercury column.

鈭�h鈥�=Pgas

Now, the difference in height of the mercury column is :

鈭�h鈥�=鈥�3.56鈥�cm

Convert m into mm,

鈥�鈥�鈥�鈥�鈥�鈥�1鈥�cmHg鈥�=鈥�10鈥�mmHg鈬�3.56鈥�cmHg鈥�=鈥�35.6鈥�mmHg

So, the pressure is 35.6 mmHg.
02

Conversion of unit from mmHg to Pascal (Pa) 

1 mmHg = 133.322 Pa

Now, the pressure is,

35.6鈥�mmHg鈥�鈥�脳133.322鈥�Pa1鈥�鈥�mmHg鈥�鈥�=鈥�鈥�4.75脳103鈥�Pa

Thus, the pressure of the gas is 4.75鈥�脳10鈥�3鈥�Pa.

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Most popular questions from this chapter

You have 357 mL of chlorine trifluoride gas at 699 mmHg and 45掳C. What is the mass (in g) of the sample?

How does a sample of gas differ in its behavior from a sample of liquid in each of the following situations?

(a) The sample is transferred from one container to a larger one.

(b) The sample is heated in an expandable container, but no change of state occurs.

(c) The sample is placed in a cylinder with a piston, and an external force is applied.

What is the effect of the following on the volume of 1 mol of an ideal gas?

(a) Temperature decreases from 800 K to 400 K (at constantP).

(b) Temperature increases from 250掳Cto 500掳C(at constantP).

(c) Pressure increases from 2 atm to 6 atm (at constant T).

If the sample flask in Figure P5.12 is open to the air, what is the atmospheric pressure (in atm)?

On a cool, rainy day, the barometric pressure is 730 mmHg. Calculate the barometric pressure in centimeters of water (cmH2O) (dof Hg = 13.5 g/mL; dof H2O = 1.00 g/mL).
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