Q18.180CP Putrescine,[NH2(CH2)4NH2]聽found... [FREE SOLUTION]

Chapter 18: Q18.180CP (page 829)

Putrescine, $[{NH}_{2} {({CH}_{2})}_{4} {NH}_{2}]$ foundin rotting animal tissue, is now known to be in all cells and essential for normal and abnormal (cancerous) growth. It also plays a key role in the formation of GABA, a neurotransmitter. A aqueous solution of putrescine has[ $O H^{-}]$ = ${2.1脳10}^{-3}$ . What isthe $K_{b}$ ?

Short Answer

Expert verified

_{$K_{b} {=4.41脳10}^{-5}$}

Step by step solution

To find Kb

$[{NH}_{2} {({CH}_{2})}_{4} {NH}_{2}] =0.10M [{OH}^{-}] {=2.1脳10}^{-3}$ First, write the reaction equation of putescine with water.

${NH}_{2} {({CH}_{2})}_{4} {NH}_{2} + H_{2} O 鈬� {NH}_{2} {({CH}_{2})}_{4} {NH}_{3}^{+} + {OH}^{鈭�}$ Next, write the $K_{b}$ expression.

$\begin{array}{l} K_{b} = \frac{[product]}{[reactant]} \\ K_{b} = \frac{[{NH}_{2} {({CH}_{2})}_{4} {NH}_{3}^{+}] [{OH}^{-}]}{[{NH}_{2} {({CH}_{2})}_{4} {NH}_{2}]} \end{array}$

Note that $[{OH}^{-}] = [{NH}_{2} {({CH}_{2})}_{4} {NH}_{3}^{+}]$ since they are produced 1 mole each.

$\begin{matrix} K_{b} = \frac{[{NH}_{2} {({CH}_{2})}_{4} {NH}_{3}^{+}] [{OH}^{-}]}{[{NH}_{2} {({CH}_{2})}_{4} {NNH}_{2}]} \\ = \frac{{[{OH}^{-}]}^{2}}{[{NH}_{2} {({CH}_{2})}_{4} {NH}_{2}]} \\ = \frac{{({2.1脳10}^{-3})}^{2}}{0.10} \\ K_{b} {=4.41脳10}^{-5} \end{matrix}$

Hence $K_{b} {=4.41脳10}^{-5}$

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To find Kb

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91影视

Putrescine,[NH2(CH2)4NH2]foundin rotting animal tissue, is now known to be in all cells and essential for normal and abnormal (cancerous) growth. It also plays a key role in the formation of GABA, a neurotransmitter. A aqueous solution of putrescine has[OH-]=2.1脳10-3. What istheKb?

Short Answer

Step by step solution

To find Kb

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Kinetics

Chemistry Branches

Ionic and Molecular Compounds

Physical Chemistry

Chemical Reactions

Study anywhere. Anytime. Across all devices.