/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 81 Write a balanced equation for th... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Problem 81

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Ozone decomposes to dioxygen. (b) Xenon reacts with fluorine. (Write three different equations.) (c) Sulfur reacts with hydrogen gas. (d) Fluorine reacts with water.

Short Answer

Expert verified
(a) \(2 O_3 \rightarrow 3 O_2\) (b) \(Xe + 3 F_2 \rightarrow XeF_6\); \(Xe + 2 F_2 \rightarrow XeF_4\); \(Xe + F_2 \rightarrow XeF_2\) (c) \(S + H_2 \rightarrow H_2S\) (d) \(2 F_2 + 2 H_2O \rightarrow 4 HF + O_2\)

Step by step solution

01

(a) Ozone decomposes to dioxygen

In this reaction, ozone (O3) decomposes to dioxygen (O2). To balance the equation, we need to make sure that the number of oxygen atoms on both sides of the equation is equal. The balanced equation for this reaction is: \[2 O_3 \rightarrow 3 O_2\]
02

(b) Xenon reacts with fluorine (first equation)

In this case, xenon (Xe) reacts with fluorine (F2) to form xenon hexafluoride (XeF6). To balance the equation, we need to make sure that the number of xenon and fluorine atoms on both sides of the equation is equal. The balanced equation for this reaction is: \[Xe + 3 F_2 \rightarrow XeF_6\]
03

(b) Xenon reacts with fluorine (second equation)

Another possible reaction between xenon and fluorine involves the formation of xenon tetrafluoride (XeF4). The balanced equation for this reaction is: \[Xe + 2 F_2 \rightarrow XeF_4\]
04

(b) Xenon reacts with fluorine (third equation)

Lastly, xenon can also react with fluorine to form xenon difluoride (XeF2). The balanced equation for this reaction is: \[Xe + F_2 \rightarrow XeF_2\]
05

(c) Sulfur reacts with hydrogen gas

In this case, sulfur (S) reacts with hydrogen gas (H2) to form hydrogen sulfide (H2S). To balance the equation, we need to make sure that the number of sulfur and hydrogen atoms on both sides of the equation is equal. The balanced equation for this reaction is: \[S + H_2 \rightarrow H_2S\]
06

(d) Fluorine reacts with water

When fluorine (F2) reacts with water (H2O), it forms hydrogen fluoride (HF) and oxygen (O2). To balance the equation, we need to make sure that the number of fluorine, hydrogen, and oxygen atoms on both sides of the equation is equal. The balanced equation for this reaction is: \[2 F_2 + 2 H_2O \rightarrow 4 HF + O_2\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Chlorine reacts with oxygen to form \(\mathrm{Cl}_{2} \mathrm{O}_{7} .\) (a) What is the name of this product (see Table 2.6)? (b) Write a balanced equation for the formation of \(\mathrm{Cl}_{2} \mathrm{O}_{7}(l)\) from the elements. (c) Under usual conditions, \(\mathrm{Cl}_{2} \mathrm{O}_{7}\) is a colorless liquid with a boiling point of \(81^{\circ} \mathrm{C}\). Is this boiling point expected or surprising? (d) Would you expect \(\mathrm{Cl}_{2} \mathrm{O}_{7}\) to be more reactive toward \(\mathrm{H}^{+}(a q)\) or \(\mathrm{OH}^{-}(a q) ?\) Explain.

Write the electron configuration for (a) the \(\mathrm{Ni}^{2+}\) ion and (b) the \(\mathrm{Sn}^{2+}\) ion. How many unpaired electrons does each contain?

Moseley established the concept of atomic number by studying X-rays emitted by the elements. The X-rays emitted by some of the elements have the following wavelengths: \begin{tabular}{ll} \hline Element & Wavelength (A) \\ \hline \(\mathrm{Ne}\) & \(14.610\) \\ \(\mathrm{Ca}\) & \(3.358\) \\ \(\mathrm{Zn}\) & \(1.435\) \\ \(\mathrm{Zr}\) & \(0.786\) \\ \(\mathrm{Sn}\) & \(0.491\) \\ \hline \end{tabular} (a) Calculate the frequency, \(\nu\), of the \(X\) -rays emitted by each of the elements, in Hz. (b) Using graph paper (or

(a) If the core electrons were totally effective at shielding the valence electrons and the valence electrons provided no shielding for each other, what would be the effective nuclear charge acting on the 3 s and \(3 p\) valence electrons in \(P\) ? (b) Repeat these calculations using Slater's rules. (c) Detailed calculations indicate that the effective nuclear charge is \(5.6+\) for the 3 s electrons and \(4.9+\) for the \(3 p\) electrons. Why are the values for the 3 s and \(3 p\) electrons different? (d) If you remove a single electron from a \(\mathrm{P}\) atom, which orbital will it come from? Explain.

Nearly all the mass of an atom is in the nucleus, which has a very small radius. When atoms bond together (for example, two fluorine atoms in \(\mathrm{F}_{2}\) ), why is the distance separating the nuclei so much larger than the radii of the nuclei?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Nuclear Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.