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Why does xenon react with fluorine, whereas neon does not?

Short Answer

Expert verified
Xenon reacts with fluorine due to its less tightly held valence electrons in the 5p subshell, which allows the highly reactive fluorine to form a bond. In contrast, neon's valence electrons in the 2p subshell are tightly held by its nucleus, making it difficult for fluorine to react with it.

Step by step solution

01

Understand the electronic configurations of xenon and neon

Both xenon and neon are noble gases and have complete electron shells. The electronic configurations for both elements are: - Neon (Ne): 1s虏 2s虏 2p鈦 - Xenon (Xe): 1s虏 2s虏 2p鈦 3s虏 3p鈦 3d鹿鈦 4s虏 4p鈦 4d鹿鈦 5s虏 5p鈦 Step 2:
02

Compare the electronic configurations to determine reactivity

Neon has a completely filled 2p subshell, whereas xenon has a completely filled 5p subshell. The difference here is that xenon's valence electrons (5p electrons) are farther from the nucleus compared to neon's valence electrons (2p electrons). This means xenon's valence electrons are less tightly held by the nucleus and can more easily participate in chemical reactions. Step 3:
03

Understand the properties of fluorine

Fluorine (F) is a highly reactive element due to its high electronegativity (3.98 on the Pauling scale). It has a strong tendency to accept electrons, which makes it a powerful oxidizing agent. Fluorine can form a single bond to gain one more electron and complete its valence shell (2s虏 2p鈦 to 2s虏 2p鈦). Step 4:
04

Analyze the reactivity of xenon and neon with fluorine

Due to its high electronegativity, fluorine wants to gain an electron. Since xenon's valence electrons are farther from the nucleus and are less tightly held, the highly reactive fluorine can form a bond with xenon, resulting in compounds such as xenon hexafluoride (XeF鈧). In contrast, neon's valence electrons (2p electrons) are held tightly by its nucleus, making it more difficult for fluorine to remove an electron and react with it. As a result, neon remains unreactive with fluorine. In conclusion, xenon reacts with fluorine due to its less tightly held valence electrons, which allows the highly reactive fluorine to form a bond. On the other hand, neon's valence electrons are tightly held by its nucleus, making it difficult for fluorine to react with it.

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Most popular questions from this chapter

An element \(X\) reacts with \(\mathrm{F}_{2}(g)\) to form the molecular product shown below. (a) Write a balanced equation for this reaction (do not worry about the phases for \(X\) and the product). (b) Do you think that \(X\) is a metal or nonmetal? Explain. [Section 7.6]

(a) Why are ionization energies always positive quantities? (b) Why does \(\mathrm{F}\) have a larger first ionization energy than \(\mathrm{O}\) ? (c) Why is the second ionization energy of an atom always greater than its first ionization energy?

Until the early 1960 s the group 8 A elements were called the inert gases; before that they were called the rare gases. The term rare gases was dropped after it was discovered that argon accounts for roughly \(1 \%\) of Earth's atmosphere. (a) Why was the term inert gases dropped? (b) What discovery triggered this change in name? (c) What name is applied to the group now?

One way to measure ionization energies is photoelectron spectroscopy (PES), a technique based on the photoelectric effect. em (Section 6.2) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength \(58.4 \mathrm{~nm}\). (a) What is the energy of a photon of this light, in \(\mathrm{eV}\) ? (b) Write an equation that shows the process corresponding to the first ionization energy of \(\mathrm{Hg}\). (c) The kinetic energy of the emitted electrons is measured to be \(10.75 \mathrm{eV}\). What is the first ionization energy of \(\mathrm{Hg}\), in \(\mathrm{kJ} / \mathrm{mol} ?\) (d) With reference to Figure \(7.11\), determine which of the halogen elements has a first ionization energy closest to that of mercury.

For each of the following sets of atoms and ions, arrange the members in order of increasing size: (a) \(\mathrm{Se}^{2-}, \mathrm{Te}^{2-}, \mathrm{Se}\); (b) \(\mathrm{Co}^{3+}, \mathrm{Fe}^{2+}, \mathrm{Fe}^{3+}\), (c) \(\mathrm{Ca}, \mathrm{Ti}^{4+}, \mathrm{Sc}^{3+}\) (d) \(\mathrm{Be}^{2+}, \mathrm{Na}^{+}, \mathrm{Ne}\)

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