/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 The specific heat of ethylene gl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The specific heat of ethylene glycol is \(2.42 \mathrm{~J} / \mathrm{g}-\mathrm{K} .\) How many J of heat are needed to raise the temperature of \(62.0 \mathrm{~g}\) of ethylene glycol from \(13.1^{\circ} \mathrm{C}\) to \(40.5^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
Approximately \(4188.5 \mathrm{~J}\) of heat are needed to raise the temperature of \(62.0 \mathrm{~g}\) of ethylene glycol from \(13.1^{\circ} \mathrm{C}\) to \(40.5^{\circ} \mathrm{C}\).

Step by step solution

01

Identify the given values

We have been given the following values: - Specific Heat (c) = 2.42 J/g-K - Mass (m) = 62.0 g - Initial Temperature (T1) = 13.1°C - Final Temperature (T2) = 40.5°C
02

Calculate the temperature change

We need to find the temperature change (∆T), so we subtract the initial temperature (T1) from the final temperature (T2): ∆T = T2 - T1 ∆T = 40.5°C - 13.1°C ∆T = 27.4 K
03

Use the formula to calculate the heat required

Now that we have all the values, we can use the formula: Heat (Q) = Mass (m) x Specific Heat (c) x Temperature Change (∆T) Q = (62.0 g) x (2.42 J/g-K) x (27.4 K)
04

Calculate the heat required

Multiply the values to get the result: Q = 62.0 x 2.42 x 27.4 Q ≈ 4188.5 J So, approximately 4188.5 J of heat are needed to raise the temperature of 62.0 g of ethylene glycol from 13.1°C to 40.5°C.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

It is estimated that the net amount of carbon dioxide fixed by photosynthesis on the landmass of Earth is \(5.5 \times\) \(10^{16} \mathrm{~g} / \mathrm{yr}\) of \(\mathrm{CO}_{2}\). Assume that all this carbon is converted into glucose. (a) Calculate the energy stored by photosynthesis on land per year in \(\mathrm{kJ}\). (b) Calculate the average rate of conversion of solar energy into plant energy in MW \((1 \mathrm{~W}=1 \mathrm{~J} / \mathrm{s})\). A large nuclear power plant produces about \(10^{3} \mathrm{MW}\). The energy of how many such nuclear power plants is equivalent to the solar energy conversion?

Consider the combustion of a single molecule of \(\mathrm{CH}_{4}(g)\) forming \(\mathrm{H}_{2} \mathrm{O}(l)\) as a product. (a) How much energy, in J. is produced during this reaction? (b) A typical X-ray photon has an energy of \(8 \mathrm{keV}\). How does the energy of combustion compare to the energy of the X-ray photon?

At \(20^{\circ} \mathrm{C}\) (approximately room temperature) the average velocity of \(\mathrm{N}_{2}\) molecules in air is \(1050 \mathrm{mph}\). (a) What is the average speed in \(\mathrm{m} / \mathrm{s}\) ? (b) What is the kinetic energy (in J) of an \(\mathrm{N}_{2}\) molecule moving at this speed? (c) What is the total kinetic energy of \(1 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) molecules moving at this speed?

For the following processes, calculate the change in internal energy of the system and determine whether the process is endothermic or exothermic: (a) A balloon is heated by adding 850 J of heat. It expands, doing \(382 \mathrm{~J}\) of work on the atmosphere. (b) A \(50-g\) sample of water is cooled from \(30^{\circ} \mathrm{C}\) to \(15^{\circ} \mathrm{C}\), thereby losing approximately \(3140 \mathrm{~J}\) of heat. (c) A chemical reaction releases \(6.47 \mathrm{~kJ}\) of heat and does no work on the surroundings.

Imagine that you are climbing a mountain. (a) Is the distance you travel to the top a state function? Why or why not? (b) Is the change in elevation between your base camp and the peak a state function? Why or why not? [Section 5.2]

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.