/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Imagine that you are climbing a ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 4

Imagine that you are climbing a mountain. (a) Is the distance you travel to the top a state function? Why or why not? (b) Is the change in elevation between your base camp and the peak a state function? Why or why not? [Section 5.2]

Short Answer

Expert verified
(a) The distance traveled to the top of a mountain is not a state function because it depends on the chosen path and is path-dependent. (b) The change in elevation between the base camp and the peak is a state function because it only depends on the initial and final points of the ascent and is path-independent.

Step by step solution

01

(a) Determine if the distance to the top is a state function

To find out if the distance a person travels to the top of a mountain is a state function, we have to determine if this quantity is path-independent. That is, does the distance depend only on the current state of the person's ascent? In general, the path a person takes to climb a mountain could be different each time they climb it. Therefore, the distance traveled to reach the top depends on the chosen path. Since it is path-dependent, the distance traveled is not a state function.
02

(b) Determine if the change in elevation is a state function

For the change in elevation between the base camp and the peak, we'll again determine if this quantity is path-independent. Let's analyze if the change in elevation depends only on the initial and final points of the ascent. Both the base camp and the peak have fixed elevations, and the difference between these elevations will be the same regardless of the path taken to climb the mountain. As a result, the change in elevation is path-independent, and thus, the change in elevation is a state function.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When a mole of dry ice, \(\mathrm{CO}_{2}(s)\), is converted to \(\mathrm{CO}_{2}(g)\) at atmospheric pressure and \(-78{ }^{\circ} \mathrm{C}\), the heat absorbed by the system exceeds the increase in internal energy of the \(\mathrm{CO}_{2}\). Why is this so? What happens to the remaining energy?

From the enthalpies of reaction \(\begin{aligned} 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) & \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g) & \Delta H &=-483.6 \mathrm{~kJ} \\ 3 \mathrm{O}_{2}(g) & \cdots &-\cdots & 2 \mathrm{O}_{3}(g) & \Delta H &=+284.6 \mathrm{~kJ} \end{aligned}\) calculate the heat of the reaction $$ 3 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{3}(\mathrm{~g}) \longrightarrow 3 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) $$

The decomposition of zinc carbonate, \(\mathrm{ZnCO}_{3}(s)\), into zinc oxide, \(\mathrm{ZnO}(\mathrm{s})\), and \(\mathrm{CO}_{2}(\mathrm{~g})\) at constant pressure requires the addition of \(71.5 \mathrm{~kJ}\) of heat per mole of \(\mathrm{ZnCO}_{3}\). (a) Write a balanced thermochemical equation for the reaction. (b) Draw an enthalpy diagram for the reaction.

At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat \(\mathrm{KClO}_{3}\) : \(2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g) \quad \Delta H=-89.4 \mathrm{~kJ}\) For this reaction, calculate \(\Delta H\) for the formation of (a) \(0.632 \mathrm{~mol}\) of \(\mathrm{O}_{2}\) and (b) \(8.57 \mathrm{~g}\) of \(\mathrm{KCl}\). (c) The decomposition of \(\mathrm{KClO}_{3}\) proceeds spontaneously when it is heated. Do you think that the reverse reaction, the formation of \(\mathrm{KClO}_{3}\) from \(\mathrm{KCl}\) and \(\mathrm{O}_{2}\), is likely to be feasible under ordinary conditions? Explain your answer.

Given the data $$ \begin{aligned} \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)-\cdots+2 \mathrm{NO}(g) & \Delta H=+180.7 \mathrm{~kJ} \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \cdots-\rightarrow 2 \mathrm{NO}_{2}(g) & \Delta H=-113.1 \mathrm{~kJ} \\ 2 \mathrm{~N}_{2} \mathrm{O}(g)-\cdots 2 \mathrm{~N}_{2}(g)+\mathrm{O}_{2}(g) & \Delta H=-163.2 \mathrm{~kJ} \end{aligned} $$ use Hess's law to calculate \(\Delta H\) for the reaction $$ \mathrm{N}_{2} \mathrm{O}(g)+\mathrm{NO}_{2}(g) \stackrel{-\cdots} 3 \mathrm{NO}(g) $$
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Organic Chemistry

Read Explanation

Making Measurements

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.