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Explain why the \(d_{x y}, d_{x z}\), and \(d_{y z}\) orbitals lie lower in energy than the \(d_{z^{2}}\) and \(d_{x^{2}-y^{2}}\) orbitals in the presence of an octahedral arrangement of ligands about the central metalion.

Short Answer

Expert verified
In the presence of an octahedral arrangement of ligands, the \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals lie lower in energy than the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals because they experience less electron repulsion with the ligands. The \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals have lobes oriented between the axes, while the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals have lobes along the axes, where ligands approach. Consequently, the orbitals with lobes along the axes face greater electron repulsion leading to higher energy levels and decreased stability compared to the orbitals with lobes between the axes.

Step by step solution

01

Understand the orientation of d-orbitals in octahedral field

First, we need to visualize the orientation of the five d鈥恛rbitals in an octahedral field: \(d_{xy}, d_{xz}, d_{yz}, d_{z^2}\), and \(d_{x^2-y^2}\). The \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals have lobes oriented between the axes, while the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals have lobes along the axes.
02

Visualize octahedral arrangement of ligands

In an octahedral arrangement, ligands are approaching the metal ion from the positive and negative directions of the x, y, and z axes. So, there are ligands along all the axes.
03

Examine electron repulsion

The energy of the orbitals is affected by the electron repulsion between the metal ion d-orbitals and the ligands' electron pairs. When ligands approach the metal ion, the d-orbitals with lobes along the axes (i.e., \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals) will experience greater electron repulsion than those with lobes between the axes (i.e., \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals).
04

Analyze stability and energy levels

Due to greater electron repulsion, the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals become less stable, resulting in higher energy levels compared to the \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals. In an octahedral field, the orbitals with lobes along the axes lie at a higher energy level than the orbitals with lobes between the axes.
05

Conclusion

In conclusion, the \(d_{xy}, d_{xz}\), and \(d_{yz}\) orbitals lie lower in energy than the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals in the presence of an octahedral arrangement of ligands about the central metal ion because they experience less electron repulsion with the ligands compared to the orbitals with lobes along the axes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

d-Orbitals
To fully understand the distribution of energy levels amongst the various orbitals in transition metal complexes, we first delve into what d-orbitals are. d-Orbitals are a set of five electron orbitals 鈥 denoted as dxy, dxz, dyz, dz2, and dx2-y2 鈥 that are pertinent to the atoms of transition metals.

The orientation of these d-orbitals is spatially characteristic; orbitals like dxy, dxz, and dyz exhibit lobes situated between the axes, whereas dz2 and dx2-y2 point along the x, y, and z axes. This orientation significantly influences how these orbitals interact with their surroundings, primarily the ligands that approach the metal ion, thus determining their energy levels in a coordination compound.
Ligand Field Theory
Ligand Field Theory (LFT) is a powerful tool used to explain the bonding, structure, and electronic spectra of coordination compounds. It's an adaptation of the molecular orbital theory which considers the interaction between transition metal d-orbitals and ligand groups.

Under LFT, when ligands 鈥 molecules or ions that donate at least one pair of electrons to a central atom 鈥 approach a transition metal ion, they generate an electrostatic field that affects the energy of the d-orbitals. The closeness of the ligands and the direction of their approach result in different spatial interactions with these d-orbitals, leading to what is known as crystal field splitting. It is the dissimilar energies of the d-orbitals after the crystal field has been established that is foundational in understanding various properties of coordination complexes.
Crystal Field Stabilization Energy
When discussing Crystal Field Theory (CFT), the concept of Crystal Field Stabilization Energy (CFSE) emerges as a crucial component in the understanding of coordination complexes. CFSE is the energy difference between the energy of the d-orbitals in a spherical field (where all are degenerate) and the energy in the actual field generated by the ligands.

CFSE offers insights into the overall stability of the complex: the greater the CFSE, the more stable the complex. This is a result of the distribution of electrons in the split d-orbitals, where electrons seek to fill the lower-energy d-orbitals (dxy, dxz, and dyz) first, in line with the Aufbau principle, causing these orbitals to have lower energies in an octahedral field compared to those that experience greater repulsion (dz2 and dx2-y2). This difference in energy is the physical manifestation of CFSE.
Electron Repulsion
At the heart of why different d-orbitals have different energies in the context of LFT and CFT lies the fundamental principle of electron repulsion. Each ligand contains electron pairs that, when they approach the metal ion, interact electrostatically with the electrons in the d-orbitals of the metal.

Orbitals with lobes directed along the axis where ligands approach (dz2 and dx2-y2) will naturally experience a greater repulsive interaction with these approaching ligand electrons, compared to orbitals with lobes oriented between the axes (dxy, dxz, and dyz). This repulsion raises the energy of the orbitals, making the ones along the axes less energetically favorable, thus higher in energy, in accordance with Pauli's Exclusion Principle and Coulomb's Law. Understanding this electron repulsion is key in explaining the crystal field splitting that occurs within octahedral coordination complexes.

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Most popular questions from this chapter

A manganese complex formed from a solution containing potassium bromide and oxalate ion is purified and analyzed. It contains \(10.0 \% \mathrm{Mn}, 28.6 \%\) potassium, \(8.8 \%\) carbon, and \(29.2 \%\) bromine by mass. The remainder of the compound is oxygen. An aqueous solution of the complex has about the same electrical conductivity as an equimolar solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\). Write the formula of the compound, using brackets to denote the manganese and its coordination sphere.

Polydentate ligands can vary in the number of coordination positions they occupy. In each of the following, identify the polydentate ligand present and indicate the probable number of coordination positions it occupies: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}(0-\mathrm{phen})\right] \mathrm{Cl}_{3}\) (b) \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{Br}\) (c) \(\left[\mathrm{Cr}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}\) (d) \(\left[\mathrm{Zn}(\mathrm{en})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

Indicate the likely coordination number of the metal in each of the following complexes: (a) \(\left[\mathrm{Rh}(\mathrm{bipy})_{3}\right]\left(\mathrm{NO}_{3}\right)_{3}\) (b) \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2} \mathrm{Cl}_{2}\right]\) (c) \(\left[\mathrm{Cr}(\mathrm{o} \text { -phen })_{3}\right]\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{3}\) (d) \(\mathrm{Na}_{2}[\mathrm{Co}(\mathrm{EDTA}) \mathrm{Br}]\)

Oxyhemoglobin, with an \(\mathrm{O}_{2}\) bound to iron, is a low-spin \(\mathrm{Fe}(\mathrm{II})\) complex; deoxyhemoglobin, without the \(\mathrm{O}_{2}\) molecule, is a high-spin complex. (a) Assuming that the coordination environment about the metal is octahedral, how many unpaired electrons are centered on the metal ion in each case? (b) What ligand is coordinated to the iron in place of \(\mathrm{O}_{2}\) in deoxyhemoglobin? (c) Explain in a general way why the two forms of hemoglobin have different colors (hemoglobin is red, whereas deoxyhemoglobin has a bluish cast). (d) A 15-minute exposure to air containing 400 ppm of CO causes about \(10 \%\) of the hemoglobin in the blood to be converted into the carbon monoxide complex, called carboxyhemoglobin. What does this suggest about the relative equilibrium constants for binding of carbon monoxide and \(\mathrm{O}_{2}\) to hemoglobin?

Sketch all the possible stereoisomers of (a) tetrahedral \(\left[\mathrm{Cd}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2} \mathrm{Cl}_{2}\right]\), (b) square-planar \(\left[\mathrm{IrCl}_{2}\left(\mathrm{PH}_{3}\right)_{2}\right]^{-}\), (c) octa- hedral \(\left[\mathrm{Fe}(0 \text { -phen })_{2} \mathrm{Cl}_{2}\right]^{+}\)

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