/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Write the formula for each of th... [FREE SOLUTION] | 91影视

91影视

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaamminechromium(III) nitrate (b) tetraamminecarbonatocobalt(III) sulfate (c) dichlorobis(ethylenediamine)platinum(IV) bromide (d) potassium diaquatetrabromovanadate(III) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

Short Answer

Expert verified
The short versions of the chemical formulas for the given coordination compounds are as follows: (a) hexaamminechromium(III) nitrate: \([Cr(NH_3)_6](NO_3)_3\) (b) tetraamminecarbonatocobalt(III) sulfate: \([Co(NH_3)_4CO_3](SO_4)\) (c) dichlorobis(ethylenediamine)platinum(IV) bromide: \([PtCl_2(en)_2](Br)_2\) (d) potassium diaquatetrabromovanadate(III): \(K[V(OH_2)_2Br_4]\) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II): \([Zn(en)_2](HgI_4)\)

Step by step solution

01

Identify the central atom and counter ion

The central atom of this coordination complex is chromium (Cr). The compound is hexaamminechromium(III), which means that Cr has an oxidation state of 3. The counter ion is nitrate (NO鈧冣伝).
02

Write the formula for the coordination sphere

There are six ammine ligands (NH鈧) and one chromium(III), so the coordination sphere is [Cr(NH鈧)鈧哴鲁鈦.
03

Balance the overall charge with counter ions

Since the charge of the coordination sphere is +3, we need three nitrate anions for a neutral compound. So, the formula of hexaamminechromium(III) nitrate is [Cr(NH鈧)鈧哴(NO鈧)鈧. (b) tetraamminecarbonatocobalt(III) sulfate
04

Identify the central atom and counter ion

The central atom is cobalt (Co) in the +3 oxidation state. The counter ion is sulfate (SO鈧劼测伝).
05

Write the formula for the coordination sphere

The complex has four ammine ligands (NH鈧) and one carbonate ligand (CO鈧兟测伝). The coordination sphere is [Co(NH鈧)鈧凜O鈧僝鈦.
06

Balance the overall charge with counter ions

Since the charge of the coordination sphere is +1, we need one sulfate anion to form a neutral compound. The formula for tetraamminecarbonatocobalt(III) sulfate is [Co(NH鈧)鈧凜O鈧僝(SO鈧). (c) dichlorobis(ethylenediamine)platinum(IV) bromide
07

Identify the central atom and counter ion

The central atom is platinum (Pt) in the +4 oxidation state. The counter ion is bromide (Br鈦).
08

Write the formula for the coordination sphere

The complex has two chloro ligands (Cl鈦) and two ethylenediamine ligands (en). The coordination sphere is [PtCl鈧(en)鈧俔虏鈦.
09

Balance the overall charge with counter ions

Since the charge of the coordination sphere is +2, we need two bromide anions to form a neutral compound. The formula for dichlorobis(ethylenediamine)platinum(IV) bromide is [PtCl鈧(en)鈧俔(Br)鈧. (d) potassium diaquatetrabromovanadate(III)
10

Identify the central atom and counter ion

The central atom is vanadium (V) in the +3 oxidation state. The counter ion is potassium (K鈦).
11

Write the formula for the coordination sphere

The complex has two aqua ligands (H鈧侽) and four bromo ligands (Br鈦). The coordination sphere is [V(OH鈧)鈧侭r鈧刔鈦.
12

Balance the overall charge with counter ions

Since the charge of the coordination sphere is -1, we need one potassium cation to form a neutral compound. The formula for potassium diaquatetrabromovanadate(III) is K[V(OH鈧)鈧侭r鈧刔. (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)
13

Identify the central atom and counter ion

The central atom is zinc (Zn) in the +2 oxidation state. The counter ion is tetraiodomercurate(II), which is HgI鈧劼测伝.
14

Write the formula for the coordination sphere

The complex has two ethylenediamine ligands (en). The coordination sphere is [Zn(en)鈧俔虏鈦.
15

Balance the overall charge with counter ions

Since the charge of the coordination sphere is +2, we need one tetraiodomercurate(II) anion to form a neutral compound. The formula for bis(ethylenediamine) zinc(II) tetraiodomercurate(II) is [Zn(en)鈧俔(HgI鈧).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The molecule dimethylphosphinoethane \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{PCH}_{2}-\mathrm{CH}_{2} \mathrm{P}\left(\mathrm{CH}_{3}\right)_{2}\right.\), which is abbreviated \(\left.\mathrm{dmpe}\right]\) is used as a ligand for some complexes that serve as catalysts. A complex that contains this ligand is \(\mathrm{Mo}(\mathrm{CO})_{4}(\) dmpe \()\). (a) Draw the Lewis structure for dmpe, and compare it with ethylenediammine as a coordinating ligand. (b) What is the oxidation state of Mo in \(\mathrm{Na}_{2}\left[\mathrm{Mo}(\mathrm{CN})_{2}(\mathrm{CO})_{2}(\mathrm{dmpe})\right] ?\) (c) Sketch the structure of the \(\left[\mathrm{Mo}(\mathrm{CN})_{2}(\mathrm{CO})_{2}(\mathrm{dmpe})\right]^{2-}\) ion, including all the possible isomers.

Polydentate ligands can vary in the number of coordination positions they occupy. In each of the following, identify the polydentate ligand present and indicate the probable number of coordination positions it occupies: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}(0-\mathrm{phen})\right] \mathrm{Cl}_{3}\) (b) \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{Br}\) (c) \(\left[\mathrm{Cr}(\mathrm{EDTA})\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{-}\) (d) \(\left[\mathrm{Zn}(\mathrm{en})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

For each of the following metals, write the electronic configuration of the atom and its \(3+\) ion: (a) \(\mathrm{Ru}\), (b) Mo, (c) Co. Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(3+\) ion, assuming a weak-field complex. How many unpaired electrons are there in each case?

The \(E^{\circ}\) values for two iron complexes in acidic solution are as follows: \(\begin{aligned}\left[\mathrm{Fe}(\mathrm{o}-\mathrm{phen})_{3}\right]^{3+}(a q)+\mathrm{e}^{-} & \rightleftharpoons\left[\mathrm{Fe}(\mathrm{o}-\mathrm{phen})_{3}\right]^{2+}(a q) & E^{\circ}=1.12 \mathrm{~V} \\\\\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}(a q)+\mathrm{e}^{-} & \rightleftharpoons\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}(a q) & E^{\circ} &=0.36 \mathrm{~V} \end{aligned}\) (a) What do the relative \(E^{\circ}\) values tell about the relative stabilities of the Fe(II) and Fe(III) complexes in each case? (b) Account for the more positive \(E^{\circ}\) value for the

(a) Draw the two linkage isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\). (b) Draw the two geometric isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\). (c) Two compounds with the formula \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{ClBr}\) can be prepared. Use structural formulas to show how they differ. What kind of isomerism does this illustrate?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.