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Chapter 22: Problem 82

Write a balanced equation for each of the following reactions: (a) Diborane reacts with water to form boric acid and molecular hydrogen. (b) Upon heating, boric acid undergoes a condensation reaction to form tetraboric acid. (c) Boron oxide dissolves in water to give a solution of boric acid.

Short Answer

Expert verified
(a) B鈧咹鈧佲倐 + 6H鈧侽 鈫� 6H鈧傿O鈧� + 3H鈧� (b) 4H鈧傿O鈧� 鈫� H鈧侭鈧凮鈧� + 5H鈧侽 (c) B鈧侽鈧� + 3H鈧侽 鈫� 2H鈧傿O鈧�

Step by step solution

01

(a) Diborane reacts with water to form boric acid and molecular hydrogen.

First, write the chemical formulas of the reactants and products: Diborane: B鈧咹鈧佲倐 Water: H鈧侽 Boric acid: H鈧傿O鈧� Molecular hydrogen: H鈧� Then, write the initial unbalanced equation and balance it: B鈧咹鈧佲倐 + H鈧侽 鈫� H鈧傿O鈧� + H鈧� Balanced equation: B鈧咹鈧佲倐 + 6H鈧侽 鈫� 6H鈧傿O鈧� + 3H鈧�
02

(b) Upon heating, boric acid undergoes a condensation reaction to form tetraboric acid.

Write the chemical formulas of the reactants and products: Boric acid: H鈧傿O鈧� Tetraboric acid: H鈧侭鈧凮鈧� Then, write the initial unbalanced equation and balance it: H鈧傿O鈧� 鈫� H鈧侭鈧凮鈧� Balanced equation: 4H鈧傿O鈧� 鈫� H鈧侭鈧凮鈧� + 5H鈧侽
03

(c) Boron oxide dissolves in water to give a solution of boric acid.

Write the chemical formulas of the reactants and products: Boron oxide: B鈧侽鈧� Water: H鈧侽 Boric acid: H鈧傿O鈧� Then, write the initial unbalanced equation and balance it: B鈧侽鈧� + H鈧侽 鈫� H鈧傿O鈧� Balanced equation: B鈧侽鈧� + 3H鈧侽 鈫� 2H鈧傿O鈧�

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