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Calculate the number of \(\mathrm{H}^{+}(a q)\) ions in \(1.0 \mathrm{~mL}\) of pure water at \(25^{\circ} \mathrm{C}\)

Short Answer

Expert verified
There are approximately \(6.022 \times 10^{13}\) H鈦 ions in 1.0 mL of pure water at 25掳C.

Step by step solution

01

Find the concentration of H鈧僌鈧 ions in water at 25掳C

At 25掳C, the autoionization constant of water (Kw) is given by: \[K_\mathrm{w} = [\mathrm{H}^{+}][\mathrm{OH}^{-}] = 1.0 \times 10^{-14} \mathrm{mol^2/L^2}\] Since the concentrations of \(\mathrm{H}^{+}\) ions and \(\mathrm{OH}^{-}\) ions are equal in pure water, we have: \[[\mathrm{H}^{+}] = [\mathrm{OH}^{-}]\] So, to find the concentration of \(\mathrm{H}^{+}\) ions, we can write: \[[\mathrm{H}^{+}]^2 = 1.0 \times 10^{-14}\]
02

Solve for the concentration of H鈦 ions

To find the concentration of \(\mathrm{H}^{+}\) ions, take the square root of both sides of the equation: \[[\mathrm{H}^{+}] = \sqrt{1.0 \times 10^{-14}}\] \[[\mathrm{H}^{+}] = 1 .0 \times 10^{-7} \mathrm{M}\] The concentration of H鈦 ions in water at 25掳C is \(1 .0 \times 10^{-7} \mathrm{M}\).
03

Convert the volume of water to liters

We are given the volume of water as 1.0 mL. Convert this to liters: \[1.0 \mathrm{mL} \times \frac{1 \mathrm{L}}{1000 \mathrm{mL}} = 0.001 \mathrm{L}\]
04

Calculate the number of moles of H鈦 ions in the given volume of water

To find the number of moles of H鈦 ions present in 1.0 mL of water, multiply the concentration of H鈦 ions by the volume of water in liters: \[\mathrm{moles\:of\:H^+} = (1.0 \times 10^{-7} \mathrm{M}) \times (0.001 \mathrm{L}) = 1.0 \times 10^{-10} \mathrm{mol}\]
05

Calculate the number of H鈦 ions using Avogadro's number

Finally, to find the number of \(\mathrm{H}^{+}\) ions in 1.0 mL of water, multiply the number of moles by Avogadro's number (\(6.022 \times 10^{23} \mathrm{ions/mol}\)): \[\mathrm{number\:of\:H^+} = (1.0 \times 10^{-10}\mathrm{mol}) \times (6.022 \times 10^{23} \mathrm{ions/mol}) = 6.022 \times 10^{13} \mathrm{ions}\] So there are approximately \(6.022 \times 10^{13}\) H鈦 ions in 1.0 mL of pure water at 25掳C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concentration of H鈦 Ions
The concentration of \( \mathrm{H}^{+} \) ions in water is an essential concept when studying water's autoionization. At 25掳C, pure water undergoes a slight dissociation into \( \mathrm{H}^{+} \) and \( \mathrm{OH}^{-} \) ions, resulting in an equilibrium constant known as the water autoionization constant, denoted by \( K_w \). This constant is expressed as: \[ K_w = [\mathrm{H}^{+}][\mathrm{OH}^{-}] = 1.0 \times 10^{-14} \mathrm{mol^2/L^2} \] In pure water, the concentrations of \( \mathrm{H}^{+} \) ions and \( \mathrm{OH}^{-} \) ions are equal. Thus, we can say: \[ [\mathrm{H}^{+}] = \sqrt{1.0 \times 10^{-14}} = 1.0 \times 10^{-7} \mathrm{M} \] This concentration tells us that in each liter of pure water at 25掳C, there are \( 1.0 \times 10^{-7} \) moles of \( \mathrm{H}^{+} \) ions. By knowing this value, we can progress to determining quantities such as the number of moles or even the exact count of ions with further calculations.
Avogadro's Number
Avogadro's number is a key concept in chemistry that defines the number of particles, typically atoms or ions, in one mole of a substance. This constant is approximately \( 6.022 \times 10^{23} \) particles/mol.This means when you have one mole of \( \mathrm{H}^{+} \) ions, you're essentially holding \( 6.022 \times 10^{23} \) ions. Avogadro's number is crucial for converting between moles of a substance and the actual number of discrete particles.Using our exercise as an example, if we've calculated the moles of \( \mathrm{H}^{+} \) ions in a certain volume of water, we can use Avogadro鈥檚 number to find out exactly how many \( \mathrm{H}^{+} \) ions are present. So even though the notion of a mole connects the atomic scale to the human scale, Avogadro's number gives us a practical way to count out these billions and billions of tiny entities that make up matter.
Moles of H鈦 Ions
The concept of moles is a cornerstone of chemistry, especially when dealing with tiny particles like \( \mathrm{H}^{+} \) ions. A mole allows chemists to count particles at the atomic scale by using a large number, Avogadro鈥檚 number.When you know the concentration of \( \mathrm{H}^{+} \) ions in a solution (like in pure water at 25掳C, where it's \( 1.0 \times 10^{-7} \mathrm{M} \)), and you also know the volume of the solution, you can calculate the moles of \( \mathrm{H}^{+} \) ions present using the formula: \[ \mathrm{moles\ of\ H^+} = [\mathrm{H}^{+}] \times \text{Volume in liters} \]In the given problem, we converted the 1.0 mL water volume to liters (0.001 L) and multiplied it by the concentration, resulting in \( 1.0 \times 10^{-10} \) moles of \( \mathrm{H}^{+} \) ions. This calculation is simple yet powerful, as it bridges concentration with real, countable units that can be further analyzed or used in additional computations.

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Most popular questions from this chapter

(a) Which of the following is the stronger BronstedLowry acid, \(\mathrm{HNO}_{3}\) or \(\mathrm{HNO}_{2} ?\) (b) Which is the stronger Br酶nsted- Lowry base, \(\mathrm{NH}_{3}\) or \(\mathrm{H}_{2} \mathrm{O}\) ? Briefly explain your choices.

Caproic acid \(\left(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{COOH}\right)\) is found in small amounts in coconut and palm oils and is used in making artificial flavors. A saturated solution of the acid contains \(11 \mathrm{~g} / \mathrm{L}\) and has a pH of 2.94. Calculate \(K_{a}\) for the acid.

Arrange the following \(0.10 \mathrm{M}\) solutions in order of increasing acidity (decreasing pH): (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), (ii) \(\mathrm{NaNO}_{3}\), (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) (iv) \(\mathrm{NaF}\), (v) \(\mathrm{CH}_{3} \mathrm{COONa}\)

A \(0.100 \mathrm{M}\) solution of bromoacetic acid \(\left(\mathrm{BrCH}_{2} \mathrm{COOH}\right)\) is \(13.2 \%\) ionized. Calculate \(\left[\mathrm{H}^{+}\right],\left[\mathrm{BrCH}_{2} \mathrm{COO}^{-}\right]\), and \(\left[\mathrm{BrCH}_{2} \mathrm{COOH}\right]\)

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5\), indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14} ;\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6}\)

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