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(a) Which of the following is the stronger BronstedLowry acid, \(\mathrm{HNO}_{3}\) or \(\mathrm{HNO}_{2} ?\) (b) Which is the stronger Br酶nsted- Lowry base, \(\mathrm{NH}_{3}\) or \(\mathrm{H}_{2} \mathrm{O}\) ? Briefly explain your choices.

Short Answer

Expert verified
(a) HNO鈧 is the stronger Br酶nsted-Lowry acid because its conjugate base, NO鈧冣伝, is more stable due to the presence of three resonance structures that effectively spread the negative charge across multiple oxygen atoms. (b) NH鈧 is the stronger Br酶nsted-Lowry base as it has a nitrogen atom with a lower electronegativity than oxygen in H鈧侽, making it more likely to share its lone pair and accept a proton.

Step by step solution

01

1. Determine the stronger Br酶nsted-Lowry acid:

To determine the stronger acid between HNO鈧 and HNO鈧, we need to look at their conjugate bases (the species formed after losing a proton) and their stability. 鈥 For HNO鈧: After losing a proton, we get NO鈧冣伝 (nitrate ion). 鈥 For HNO鈧: After losing a proton, we get NO鈧傗伝 (nitrite ion).
02

2. Evaluate the stability of the conjugate bases:

The stability of a conjugate base is an important factor in determining the strength of an acid. A greater stability of the conjugate base implies a stronger acid. In this case, we can analyze the resonance structures to determine the stability. 鈥 NO鈧冣伝 has three resonance structures, which helps to spread the negative charge across multiple oxygen atoms, making the ion stable. 鈥 NO鈧傗伝 has two resonance structures, which do share the negative charge among oxygen atoms, but less effectively than NO鈧冣伝. Since NO鈧冣伝 is more stable than NO鈧傗伝, HNO鈧 is the stronger Br酶nsted-Lowry acid.
03

3. Determine the stronger Br酶nsted-Lowry base:

To determine the stronger base between NH鈧 and H鈧侽, we need to look at their tendencies to accept protons. 鈥 For NH鈧: It has a lone pair of electrons on the nitrogen atom, which can accept a proton. 鈥 For H鈧侽: It also has lone pairs of electrons, specifically on the oxygen atom, capable of accepting a proton.
04

4. Analyze the basicity of NH鈧 and H鈧侽:

To analyze the basic strength of NH鈧 and H鈧侽, we need to consider factors like the electronegativity of the atom which will accept the proton, and the stability of the resulting conjugate acid after accepting the proton. 鈥 NH鈧 has a nitrogen atom with a lower electronegativity than oxygen in H鈧侽. This means that NH鈧 is more likely to share its lone pair and accept a proton. 鈥 After accepting a proton, NH鈧 forms NH鈧勨伜 (ammonium ion) and H鈧侽 forms H鈧僌鈦 (hydronium ion). Both conjugate acids are stable, but the lower electronegativity of nitrogen in NH鈧 makes it a stronger base. In conclusion, NH鈧 is the stronger Br酶nsted-Lowry base.
05

5. Provide the answers:

(a) The stronger Br酶nsted-Lowry acid is HNO鈧. (b) The stronger Br酶nsted-Lowry base is NH鈧.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid Strength
When exploring the concept of acid strength, it's key to understand that it is directly connected to how readily an acid donates its proton (H+) to a base. A strong acid will dissociate completely in water, creating more H+ ions, leading to a lower pH value. In contrast, a weaker acid will not dissociate as completely, resulting in a higher pH.

Comparing (HNO_3) and (HNO_2), it is important to assess their respective conjugate bases for stability, which is covered in the upcoming sections. (HNO_3), or nitric acid, is typically considered a stronger acid than (HNO_2), or nitrous acid, because its conjugate base is more stable due to the distribution of negative charge across multiple atoms through resonance structures.
Conjugate Bases Stability
The stability of conjugate bases is a crucial part of determining the strength of their corresponding acids. A stable conjugate base means the acid will more readily give up its proton, as the base can comfortably accommodate the negative charge left behind.

The nitrate ion (NO鈧冣伝), a conjugate base of (HNO_3), displays a high degree of stability because its negative charge is delocalized across multiple oxygen atoms through resonance. The nitrite ion (NO鈧傗伝), conjugate base of (HNO_2), has less stability compared to the nitrate ion because it has fewer resonance structures, thus its ability to spread out the negative charge is limited. Therefore, (HNO_3) is stronger as an acid than (HNO_2).
Resonance Structures
Delving into resonance structures will illuminate how certain chemical species, like the aforementioned conjugate bases, can disperse their charges across a molecule or ion. Resonance structures are different ways of drawing the same molecule, showing different possible locations for double bonds and lone pairs.

Though all structures represent the same molecule, they allow us to visualize how electrons might be distributed in space. More resonance structures mean a more stable ion, as the negative charge is not localized in one place but shared across atoms. For instance, the nitrate ion鈥檚 charge is spread out across three oxygen atoms, rendering it more stable and contributing to (HNO_3) being a strong acid.
Acid-Base Reactivity
Understanding acid-base reactivity involves looking at how acids and bases interact with each other. The reactivity of an acid depends on its tendency to lose a proton, whereas the reactivity of a base depends on its propensity to gain a proton. Reactivity can be influenced by factors like molecular structure, the presence of lone pairs, and the stability of the resulting products once the reaction has occurred.

Between (NH鈧) and (H鈧侽), (NH鈧) is a stronger base, largely due to the lower electronegativity of nitrogen, which readily shares its lone pair for protonation to form (NH鈧勨伜). Water, though it has lone pairs, is less reactive as a base compared to (NH鈧), also because the oxygen atom is more electronegative, making it slightly less inclined to share electrons to form (H鈧僌鈦). Consequently, the difference in acid and base reactivity can significantly affect the outcome of chemical reactions.

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Most popular questions from this chapter

Using data from Appendix D, calculate [OH \(^{-}\) ] and pH for each of the following solutions: (a) \(0.105 \mathrm{M}\) NaF, (b) \(0.035 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S},(\mathrm{c})\) a mixture that is \(0.045 \mathrm{M}\) in \(\mathrm{CH}_{3} \mathrm{COONa}\) and \(0.055 \mathrm{M}\) in \(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{Ba} .\)

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base: \(\mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ON}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ONH}^{+}(a q)+\mathrm{OH}^{-}(a q)\) A \(0.035 \mathrm{M}\) solution of ephedrine has a pH of \(11.33 .\) (a) What are the equilibrium concentrations of \(\mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ON}, \mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ONH}^{+}\), and \(\mathrm{OH}^{-} ?\) (b) Calculate \(K_{b}\) for ephedrine.

Atmospheric \(\mathrm{CO}_{2}\) levels have risen by nearly \(20 \%\) over the past 40 years from 315 ppm to 380 ppm. (a) Given that the average pH of clean, unpolluted rain today is 5.4, determine the pH of unpolluted rain 40 years ago. Assume that carbonic acid \(\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right)\) formed by the reaction of \(\mathrm{CO}_{2}\) and water is the only factor influencing \(\mathrm{pH}\). $$ \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{CO}_{3}(a q) $$ (b) What volume of \(\mathrm{CO}_{2}\) at \(25^{\circ} \mathrm{C}\) and \(1.0 \mathrm{~atm}\) is dissolved in a 20.0-L bucket of today's rainwater?

Calculate \(\left[\mathrm{OH}^{-}\right]\) and \(\mathrm{pH}\) for (a) \(1.5 \times 10^{-3} \mathrm{M} \mathrm{Sr}(\mathrm{OH})_{2}\) (b) \(2.250 \mathrm{~g}\) of \(\mathrm{LiOH}\) in \(250.0 \mathrm{~mL}\) of solution, \((c) 100 \mathrm{~mL}\) of \(0.175 \mathrm{M} \mathrm{NaOH}\) diluted to \(2.00 \mathrm{~L},(\mathrm{~d})\) a solution formed by adding \(5.00 \mathrm{~mL}\) of \(0.105 \mathrm{M} \mathrm{KOH}\) to \(15.0 \mathrm{~mL}\) of \(9.5 \times 10^{-2} \mathrm{M} \mathrm{Ca}(\mathrm{OH})_{2}\)

(a) What is the difference between the Arthenius and the Bronsted-Lowry definitions of a base? (b) When ammonia is dissolved in water, it behaves both as an Arrhenius base and as a Bronsted-Lowry base. Explain.

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