Chapter 14: Problem 1
Write equations that show \(\mathrm{NH}_{3}\) as both a conjugate acid and a conjugate base.
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Chapter 14: Problem 1
Write equations that show \(\mathrm{NH}_{3}\) as both a conjugate acid and a conjugate base.
These are the key concepts you need to understand to accurately answer the question.
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The ionization constant for water \(\left(K_{w}\right)\) is \(2.9 \times 10^{-14}\) at \(40^{\circ} \mathrm{C}\). Calculate \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right],\left[\mathrm{OH}^{-}\right], \mathrm{pH},\) and \(\mathrm{pOH}\) for pure water at \(40^{\circ} \mathrm{C}\).
Show by suitable net ionic equations that each of the following species can act as a Bronsted-Lowry acid: (a) \(\mathrm{HNO}_{3}\) (b) \(\mathrm{PH}_{4}^{+}\) (c) \(\mathrm{H}_{2} \mathrm{S}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) (e) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (f) HS \(^{-}\)
Why is the hydronium ion concentration in a solution that is \(0.10 \mathrm{M}\) in \(\mathrm{HCl}\) and \(0.10 \mathrm{M}\) in HCOOH determined by the concentration of HCl?
From the equilibrium concentrations given, calculate \(K_{\mathrm{a}}\) for each of the weak acids and \(K_{\mathrm{b}}\) for each of the weak bases. (a) \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}:\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.34 \times 10^{-3} \mathrm{M}$$\left[\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}\right]=1.34 \times 10^{-3} \mathrm{M}$$\left[\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\right]=9.866 \times 10^{-2} \mathrm{M}\). (b) \(\mathrm{ClO}^{-}:\left[\mathrm{OH}^{-}\right]=4.0 \times 10^{-4} \mathrm{M}\) \([\mathrm{HClO}]=2.38 \times 10^{-4} \mathrm{M}$$\left[\mathrm{ClO}^{-}\right]=0.273 \mathrm{M}\). (c) \(\mathrm{HCO}_{2} \mathrm{H}:\left[\mathrm{HCO}_{2} \mathrm{H}\right]=0.524 \mathrm{M}\) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=9.8 \times 10^{-3} \mathrm{M}\) \(\left[\mathrm{HCO}_{2}^{-}\right]=9.8 \times 10^{-3} \mathrm{M}\). (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}^{+}: \quad\left[\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}^{+}\right]=0.233 \mathrm{M}\) \(\left[\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right]=2.3 \times 10^{-3} \mathrm{M}\) \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=2.3 \times 10^{-3} \mathrm{M}\).
Show by suitable net ionic equations that each of the following species can act as a Bronsted-Lowry base: (a) \(\mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{OH}^{-}\) (c) \(\mathrm{NH}_{3}\) (d) CN (e) \(\mathrm{S}^{2-}\) (f) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)
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