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Show by suitable net ionic equations that each of the following species can act as a Bronsted-Lowry acid: (a) \(\mathrm{HNO}_{3}\) (b) \(\mathrm{PH}_{4}^{+}\) (c) \(\mathrm{H}_{2} \mathrm{S}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) (e) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (f) HS \(^{-}\)

Short Answer

Expert verified
Each species can act as a Bronsted-Lowry acid by donating a proton (H+): HNO3 to H3O+ and NO3-, PH4+ to H2 and PH3, H2S to H+ and HS-, CH3CH2COOH to CH3CH2COO- and H+, H2PO4- to HPO4^2- and H+, HS- to S^2- and H+.

Step by step solution

01

Determine Bronsted-Lowry Acid

According to the Bronsted-Lowry definition, an acid is a species that donates a proton (H+). Each of the given species can donate a hydrogen ion to act as a Bronsted-Lowry acid.
02

Write Net Ionic Equations for HNO3

For HNO3: In aqueous solution, nitric acid donates a proton to water to form hydronium ion (H3O+) and nitrate ion (NO3-). \[ \mathrm{HNO}_{3} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{H}_{3}\mathrm{O}^{+} + \mathrm{NO}_{3}^{-} \]
03

Write Net Ionic Equations for PH4+

For PH4+: The tetrahydrogen phosphonium ion donates a proton to form hydrogen gas and a phosphonium ion. \[ \mathrm{PH}_{4}^{+} \rightarrow \mathrm{H}_{2} + \mathrm{PH}_{3} \]
04

Write Net Ionic Equations for H2S

For H2S: Hydrogen sulfide releases a proton to form a hydrosulfide ion. \[ \mathrm{H}_{2} \mathrm{S} \rightarrow \mathrm{H}^{+} + \mathrm{HS}^{-} \]
05

Write Net Ionic Equations for CH3CH2COOH

For CH3CH2COOH: This is propionic acid, which donates a proton to form a propionate ion. \[ \mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{COOH} \rightarrow \mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{COO}^{-} + \mathrm{H}^{+} \]
06

Write Net Ionic Equations for H2PO4-

For H2PO4-: The dihydrogen phosphate ion can donate a proton to form hydrogen phosphate ion. \[ \mathrm{H}_{2} \mathrm{PO}_{4}^{-} \rightarrow \mathrm{HPO}_{4}^{2-} + \mathrm{H}^{+} \]
07

Write Net Ionic Equations for HS-

For HS-: The hydrosulfide ion can donate a proton to form sulfide ion. \[ \mathrm{HS}^{-} \rightarrow \mathrm{S}^{2-} + \mathrm{H}^{+} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Net Ionic Equations
Net ionic equations are a fundamental concept in chemistry, simplifying reactions to show only the species that actually participate in the chemical process. These equations strip away spectator ions, which do not contribute to the overall reaction, to focus on the action at the core of the reaction.

To illustrate, let's look at an acid-base reaction featuring a Bronsted-Lowry acid. In every instance, you will notice that the equation highlights the transfer of protons (\textup{H}^+) between molecules or ions. The full molecular equation might list all reactants and products, including those that remain unchanged, but the net ionic equation only shows the active participants.

For example, when \textup{HNO}_3 acts as a Bronsted-Lowry acid, it donates a proton, and this pivotal moment is captured succinctly as: \[ \textup{HNO}_3 + \textup{H}_2\textup{O} \rightarrow \textup{H}_3\textup{O}^+ + \textup{NO}_3^- \]
Net ionic equations are crucial in understanding the essence of chemical reactions and figuring out how substances transform and interact on the ionic level.
Proton Donation
The concept of proton donation lies at the heart of the Bronsted-Lowry theory of acids and bases. In this theory, an acid is defined by its ability to donate a proton, which is simply a hydrogen ion (\textup{H}^+), to another substance. This is a central notion in understanding acid-base chemistry.

When a substance like \textup{PH}_4^+ donates a proton, it undergoes a transformation, illustrating the Bronsted-Lowry theory in action. The proton donor becomes a different species altogether after the proton transfer: \[ \textup{PH}_4^+ \rightarrow \textup{H}_2 + \textup{PH}_3\]
Each acid listed in the exercise showcases this characteristic of proton donation, a paradigm shift from just considering the presence of hydrogen to focusing on the dynamic exchange of protons in acid-base reactions. This in-depth understanding is crucial for students to master the underlying principles of acidity and reactivity in chemistry.
Acid-Base Reaction
An acid-base reaction is a process where an acid and a base interact, typically resulting in the formation of a salt and water, and is a quintessential part of chemical reactions. In the Bronsted-Lowry perspective, such reactions are viewed through the transfer of protons. Acids donate protons, while bases accept them.

For each compound provided in the exercise, we can infer its behavior in an aqueous solution. For example, \textup{H}_2\textup{S} is an acid because it donates a proton, leading to this net ionic equation: \[ \textup{H}_2\textup{S} \rightarrow \textup{H}^+ + \textup{HS}^-\]
An acid-base reaction is thus not just a mixing of substances but a complex dance of proton transfers that redefines the interacting entities. Recognizing these transformations helps students predict the outcomes of chemical reactions and grasp the nuanced roles substances play beyond their initial definitions as mere acids or bases.

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Most popular questions from this chapter

What is the effect on the concentration of ammonia, hydroxide ion, and ammonium ion when the following are added to a basic buffer solution of equal concentrations of ammonia and ammonium nitrate: (a) KI (b) \(\mathrm{NH}_{3}\) (c) HI (d) \(\mathrm{NaOH}\) (e) \(\mathrm{NH}_{4} \mathrm{Cl}\)

What are the hydronium and hydroxide ion concentrations in a solution whose pH is \(6.52 ?\)

Explain why the pH does not change significantly when a small amount of an acid or a base is added to a solution that contains equal amounts of the acid \(\mathrm{H}_{3} \mathrm{PO}_{4}\) and a salt of its conjugate base \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\).

Salicylic acid, HOC \(_{6} \mathrm{H}_{4} \mathrm{CO}_{2} \mathrm{H}\), and its derivatives have been used as pain relievers for a long time. Salicylic acid occurs in small amounts in the leaves, bark, and roots of some vegetation (most notably historically in the bark of the willow tree). Extracts of these plants have been used as medications for centuries. The acid was first isolated in the laboratory in 1838. (a) Both functional groups of salicylic acid ionize in water, with \(K_{\mathrm{a}}=1.0 \times 10^{-3}\) for the \(-\mathrm{CO}_{2} \mathrm{H}\) group and 4.2 \(\times 10^{-13}\) for the \(-\mathrm{OH}\) group. What is the \(\mathrm{pH}\) of a saturated solution of the acid (solubility \(=1.8 \mathrm{g} / \mathrm{L}\) ). (b) Aspirin was discovered as a result of efforts to produce a derivative of salicylic acid that would not be irritating to the stomach lining. Aspirin is acetylsalicylic acid, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{CO}_{2} \mathrm{H} .\) The \(-\mathrm{CO}_{2} \mathrm{H}\) functional group is still present, but its acidity is reduced, \(K_{\mathrm{a}}=3.0 \times 10^{-4} .\) What is the pH of a solution of aspirin with the same concentration as a saturated solution of salicylic acid (See Part a).

What is the effect on the concentration of hydrofluoric acid, hydronium ion, and fluoride ion when the following are added to separate solutions of hydrofluoric acid? (a) HCl (b) KF (c) NaCl (d) KOH (e) HF

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