Chapter 9: Problem 45
Which of the following molecules is (are) polar? For each polar molecule, indicate the direction of polarity-that is, which is the negative end and which is the positive end of the molecule. (a) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{Cl}\) (b) \(\mathrm{HBF}_{2}\) (d) \(\mathrm{SO}_{3}\)
Short Answer
Step by step solution
Evaluating Polarity of BeCl2
Evaluating Polarity of CH3Cl
Evaluating Polarity of HBF2
Evaluating Polarity of SO3
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronegativity
In our exercise, we see this concept at play:
- In \( \mathrm{BeCl}_2 \), chlorine has a higher electronegativity than beryllium, but the linear shape allows for dipole moments to cancel out, making the molecule nonpolar.
- For \( \mathrm{CH}_3 \mathrm{Cl} \), the electronegative chlorine creates a strong dipole moment that doesn't get canceled due to the tetrahedral shape, resulting in a polar molecule.
- The molecule \( \mathrm{HBF}_2 \) is polar because highly electronegative fluorine atoms create a dipole with the boron atom.
- Meanwhile, with \( \mathrm{SO}_3 \), despite the difference in electronegativity between sulfur and oxygen, the symmetric trigonal planar shape cancels out dipoles, leading to a nonpolar molecule.
Molecular Geometry
- \( \text{BeCl}_2 \) has a linear geometry. With two bonding pairs and no lone electron pairs on the central beryllium atom, the opposing dipole moments between beryllium and the more electronegative chlorine effectively cancel out.
- \( \text{CH}_3 \text{Cl} \) exhibits a tetrahedral shape. This results in a net dipole moment because the electrons are not symmetrically distributed, making it polar.
- \( \text{HBF}_2 \) has a trigonal planar or distorted geometry, where the arrangement allows for a net dipole moment towards the fluorine atoms, making it polar.
- \( \text{SO}_3 \) adopts a trigonal planar shape. Despite oxygen's higher electronegativity compared to sulfur, the symmetric arrangement ensures dipoles cancel, resulting in a nonpolar molecule.
Dipole Moment
- For \( \text{BeCl}_2 \), although there are bonds with dipoles due to electronegativity differences, the linear structure causes them to cancel out and result in a net dipole moment of zero, indicating no overall polarity.
- In \( \text{CH}_3 \text{Cl} \), the presence of a single electronegative chlorine atom leads to a significant dipole moment. The tetrahedral shape ensures this dipole remains unbalanced, making the molecule polar with the negative end towards chlorine.
- In \( \text{HBF}_2 \), the unbalanced placement of fluorine atoms, which are more electronegative, results in a dipole moment pointing towards these atoms. This causes an overall molecule polarity.
- Lastly, \( \text{SO}_3 \) possesses three identical dipoles in a trigonal planar configuration, allowing all its dipoles to cancel out, leaving the molecule with no net dipole moment and thus nonpolar.