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Which of the following copper(11) salts are soluble in water and which are insoluble: \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}, \mathrm{CuCO}_{3}\) \(\mathrm{Cu}_{3}\left(\mathrm{PO}_{4}\right)_{2}, \mathrm{CuCl}_{2} ?\)

Short Answer

Expert verified
\(\mathrm{Cu(NO_{3})_{2}}\) and \(\mathrm{CuCl_{2}}\) are soluble; \(\mathrm{CuCO_{3}}\) and \(\mathrm{Cu_{3}(PO_{4})_{2}}\) are insoluble.

Step by step solution

01

Understanding Solubility Rules

To determine solubility, it's important to recall the solubility rules. Generally, nitrates (NO鈧冣伝) and chlorides (Cl鈦) are soluble in water, except for a few exceptions like lead and silver chlorides. Carbonates (CO鈧兟测伝) and phosphates (PO鈧劼斥伝) are typically insoluble, except when paired with alkali metals or ammonium.
02

Analyzing Cu(NO鈧)鈧

Copper(II) nitrate, \(\mathrm{Cu\left(NO_{3}\right)_{2}}\), contains the nitrate ion. According to the solubility rules, all nitrates are soluble in water. So, \(\mathrm{Cu\left(NO_{3}\right)_{2}}\) is soluble.
03

Analyzing CuCO鈧

Copper(II) carbonate, \(\mathrm{CuCO_{3}}\), involves the carbonate ion. Carbonates are generally insoluble, with exceptions for alkali metals and ammonium, which are not present here. Thus, \(\mathrm{CuCO_{3}}\) is insoluble.
04

Analyzing Cu鈧(PO鈧)鈧

Copper(II) phosphate, \(\mathrm{Cu_{3}(PO_{4})_{2}}\), includes the phosphate ion. Phosphates are typically insoluble except with alkali metals or ammonium, neither of which is present. Therefore, \(\mathrm{Cu_{3}(PO_{4})_{2}}\) is insoluble.
05

Analyzing CuCl鈧

Copper(II) chloride, \(\mathrm{CuCl_{2}}\), contains the chloride ion. Chlorides are generally soluble in water except with silver, lead, and mercury. Copper is not an exception, so \(\mathrm{CuCl_{2}}\) is soluble.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nitrate Solubility
Nitrates are known for their excellent solubility in water. This is a classic rule in chemistry: all nitrate salts, or compounds containing the nitrate ion ( ext{NO}_3^{-}), are soluble in water. This characteristic is nearly universal, with very rare exceptions. This means that when you're dealing with a compound like copper(II) nitrate ( ext{Cu} ext{(NO}_{3} ext{)}_{2}), it will dissolve readily in water, making a clear solution.
This broad solubility is due to the nature of the nitrate ion, which is a relatively large and stable anion. It forms strong ionic interactions with water molecules, ensuring it dissolves easily.
So, whenever you encounter a nitrate compound, you can confidently predict its solubility in water. Keep in mind that solubility rules for nitrates are among the simplest and most consistent in chemistry.
Carbonate Solubility
Carbonate ions ( ext{CO}_3^{2-}) behave quite differently from nitrates when it comes to solubility. Most carbonate salts are insoluble in water. However, there are important exceptions. Those exceptions are when carbonates are paired with alkali metals like sodium or potassium, or with the ammonium ion ( ext{NH}_4^{+}).
When you consider copper(II) carbonate ( ext{CuCO}_3), it doesn't fit these exceptions because it is paired with copper, not an alkali metal or ammonium.
In this case, ext{CuCO}_3 remains insoluble in water, meaning it will not dissolve and will likely form a solid precipitate if mixed into a water-based solution.
Thus, while dealing with carbonate compounds, always check their accompanying ions to determine solubility.
Phosphate Solubility
Phosphate ions ( ext{PO}_4^{3-}) tend to follow solubility rules similar to carbonates. Generally, phosphate compounds are insoluble in water. The key exceptions here are, once again, when phosphates are combined with alkali metals such as lithium, sodium, or potassium, or with the ammonium ion.
Copper(II) phosphate ( ext{Cu}_3( ext{PO}_4)_{2}) does not meet the criteria for these exceptions.
Without the presence of any alkali metals or ammonium in the compound, it remains insoluble, which means that no matter how much you stir it in water, it won't dissolve.
This concept emphasizes the importance of knowing the companion ions of phosphate to predict whether a given phosphate compound will dissolve in water.
Chloride Solubility
Chloride ions ( ext{Cl}^-) are mostly soluble in water, which is a helpful rule in predicting chloride compound behavior in solutions. In particular, when observing compounds like copper(II) chloride ( ext{CuCl}_2), we find that it dissolves well in water, forming a clear solution. This aligns with general solubility rules.
There are, however, a few exceptions in the solubility of chlorides: they are typically insoluble when they form salts with silver ( ext{Ag}), lead ( ext{Pb}), and mercury ( ext{Hg}). These exceptions do not include copper, which is why copper(II) chloride is soluble.
Understanding these rules helps predict outcomes in chemistry experiments dealing with chloride ions, ensuring accurate and consistent results.

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Most popular questions from this chapter

Sodium sulfate, \(\mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3},\) is used as a "fixer" in black-and-white photography. Suppose you have a bottle of sodium sulfate and want to determine its purity. The thiosulfate ion can be oxidized with \(\mathrm{I}_{2}\) according to the balanced, net ionic equation \(\mathrm{I}_{2}(\mathrm{aq})+2 \mathrm{S}_{2} \mathrm{O}_{3}^{2-}(\mathrm{aq}) \longrightarrow 2 \mathrm{I}^{-}(\mathrm{aq})+\mathrm{S}_{4} \mathrm{O}_{6}^{2-}(\mathrm{aq})\) If you use \(40.21 \mathrm{mL}\) of \(0.246 \mathrm{M} \mathrm{I}_{2}\) in a titration, what is the weight percent of \(\mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}\) in a \(3.232-\mathrm{g}\) sample of impure material?

A Two students titrate different samples of the same solution of HCl using \(0.100 \mathrm{M} \mathrm{NaOH}\) solution and phenolphthalein indicator (see Figure 5.23). The first student pipets \(20.0 \mathrm{mL}\) of the HCl solution into a flask, adds 20 mL of distilled water and a few drops of phenolphthalein solution, and titrates until a lasting pink color appears. The second student pipets \(20.0 \mathrm{mL}\), of the HCl solution into a flask, adds 60 mL. of distilled water and a few drops of phenolphthalein solution, and titrates to the first lasting pink color. Each student correctly calculates the molarity of a HCl solution. What will the second student's result be? (a) four times less than the first student's result (b) four times greater than the first student's result (c) two times less than the first student's result (d) two times greater than the first student's result (e) the same as the first student's result

A The cancer chemotherapy drug cisplatin, \(\operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\) can be made by reacting (NH_) \(_{2} \mathrm{PtCl}_{4}\) with ammonia in aqueous solution. Besides cisplatin, the other product is \(\mathrm{NH}_{1} \mathrm{Cl}\) (a) Write a balanced equation for this reaction. (b) To obtain \(12.50 \mathrm{g}\) of cisplatin, what mass of \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{PtCl}_{4}\) is required? What volume of \(0.125 \mathrm{M}\) \(\mathrm{NH}_{3}\) is required? (c) Cisplatin can react with the organic compound pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N},\) to form a new compound. $$\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}(\mathrm{aq})+x \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}(\mathrm{aq}) \longrightarrow \mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}\right)_{x}(\mathrm{s})$$ Suppose you treat \(0.150 \mathrm{g}\) of cisplatin with what you believe is an excess of liquid pyridine \((1.50 \mathrm{mL}\) \(d=0.979 \mathrm{g} / \mathrm{mL}) .\) When the reaction is complete, you can find out how much pyridine was not used by titrating the solution with standardized HCl. If 37.0 mL. of \(0.475 \mathrm{M} \mathrm{HCl}\) is required to titrate the excess pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) what is the formula of the unknown compound \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}\right)_{x} ?\)

If \(6.73 \mathrm{g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) is dissolved in enough water to make \(250 .\) mL of solution, what is the molar concentration of the sodium carbonate? What are the molar concentrations of the \(\mathrm{Na}^{+}\) and \(\mathrm{CO}_{3}^{2-}\) ions?

Balance the following equations, and then write the net ionic equation. Show states for all reactants and products \((s, \ell, g, a q)\) (a) the reaction of silver nitrate and potassium iodide to give silver iodide and potassium nitrate (b) the reaction of barium hydroxide and nitric acid to give barium nitrate and water (c) the reaction of sodium phosphate and nickel(II) nitrate to give nickel(11) phosphate and sodium nitrate

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