/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Element \(^{287} 114\) decayed b... [FREE SOLUTION] | 91Ó°ÊÓ

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Element \(^{287} 114\) decayed by \(\alpha\) emission with a half-life of about \(5 s\). Write an equation for this process.

Short Answer

Expert verified
The equation is \(^{287}_{114} \text{X} \rightarrow {}^{283}_{112} \text{Y} + {}^{4}_{2} \text{He} \).

Step by step solution

01

Understanding Alpha Decay

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle. An alpha particle consists of 2 protons and 2 neutrons, which is equivalent to a helium nucleus, \[ \text{ }^{4}_{2} ext{He} \].
02

Identifying the Initial Element and Values

The problem states that element \(^{287}_{114} \ \ \text{ }\text{X}\) undergoes alpha decay. We need to identify that the initial values for the original element are mass number (A) 287 and atomic number (Z) 114.
03

Using the Alpha Decay Equation

In alpha decay, the nucleus emits an alpha particle, \(\text{ }^{4}_{2} ext{He}\), thus the new element formed will have \( A' = A - 4 \) and \(Z' = Z - 2\).
04

Determine the New Element

By applying step 3 calculations, we reduce the mass number: \[ A' = 287 - 4 = 283 \] and the atomic number: \[Z' = 114 - 2 = 112 \]. Thus, the new element is \(^{283}_{112} \ \ \text{Y} \), where Y is the element with atomic number 112.
05

Writing the Equation

The decay equation is:\[^{287}_{114} \text{X} \rightarrow {}^{283}_{112} \text{Y} + {}^{4}_{2} \text{He} \] . Here, X and Y should be replaced with the chemical symbols of the elements corresponding to atomic numbers 114 and 112, respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a fundamental process that occurs in unstable atomic nuclei. It is a random event where an unstable nucleus loses energy by emitting radiation, hence moving towards a more stable state. Radioactive decay can take several forms, including alpha, beta, and gamma decay. Each type involves different particles and processes. In the context of alpha decay, which our exercise focuses on, the nucleus emits an alpha particle. This process reduces the mass and atomic number of the original nucleus, forming a new element in the process. Radioactive decay is vital for understanding natural radioactivity and is used in various applications, such as dating archaeological finds and medical treatments.
Atomic Nucleus
The atomic nucleus is the dense core of an atom, composed of protons and neutrons, collectively known as nucleons. It carries almost all the mass of the atom and was discovered by Ernest Rutherford in the early 20th century. The number of protons, known as the atomic number, defines the type of chemical element, while the total number of protons and neutrons gives the mass number. In unstable nuclei, like those prone to alpha decay, the balance between protons and neutrons is not optimal. This instability leads to radioactive decay as the nucleus seeks a more stable configuration. Understanding the properties of the atomic nucleus is crucial for comprehending various nuclear processes, including those that release nuclear energy. Instability often arises due to:
  • A high neutron-to-proton ratio
  • Excess energy in the nucleus
These conditions lead to processes like alpha decay.
Isotope Decay
Isotopes are variants of a particular chemical element that have the same number of protons but different numbers of neutrons. This variation results in different mass numbers. Some isotopes are stable, while others are unstable and undergo radioactive decay, known as isotope decay. The decay of isotopes often leads to the transformation into a different element. In alpha decay, for instance, an isotope loses two protons and two neutrons, transforming into another element down the periodic table. For example, in the exercise, element 114 decays to form element 112 after alpha emission. Isotope decay is an important concept in fields like radiometric dating, which measures the age of materials by comparing the abundance of a radioactive isotope within the material.
Alpha Particle Emissions
Alpha particle emissions are a specific type of radioactive decay where an atomic nucleus releases an alpha particle. An alpha particle is composed of two protons and two neutrons, identical to a helium nucleus, represented by \[{}^4_2\text{He}\].Alpha emissions result in a decrease in both the atomic mass and atomic number of the original element: the mass number decreases by four and the atomic number by two. This type of decay occurs typically in heavier elements, such as uranium and radium, due to their large atomic sizes. Key characteristics of alpha decay include:
  • Formation of a new element
  • Stability is achieved
  • Decreased mass leads to energy release
Understanding alpha emissions helps in comprehending the stability of atomic nuclei and their transformations into new elements. They play a critical role in nuclear equations and are essential in nuclear physics and chemistry.

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Most popular questions from this chapter

A piece of charred bone found in the ruins of a Native American village has a \(^{14} \mathrm{C}:^{12} \mathrm{C}\) ratio that is \(72 \%\) of the radio found in living organisms. Calculate the age of the bone fragment.

Radioactive cobalt-60 is used extensively in nuclear medicine as a \(\gamma\) -ray source. It is made by a neutron capture reaction from cobalt-59, and it is a \(\beta\) emitter; \(\beta\) emission is accompanied by strong \(\gamma\) radiation. The half-life of cobalt-60 is 5.27 years. (a) How long will it take for a cobalt-60 source to decrease to one eighth of its original activity? (b) What fraction of the activity of a cobalt-60 source remains after 1.0 year?

The uranium-235 radioactive decay series, beginning with \(_{92}^{235} \mathrm{U}\) and ending with \(_{82}^{207} \mathrm{Pb},\) occurs in the following sequence: \(\alpha, \beta, \alpha, \beta, \alpha, \alpha, \alpha, \alpha, \beta, \beta, \alpha .\) Write an equation for each step in this series.

A technique to date geological samples uses rubidium-\(87,\) a long-lived radioactive isotope of rubidium \(\left(t_{1 / 2}=\right.\) \(4.8 \times 10^{10}\) years). Rubidium-87 decays by \(\beta\) emission to strontium-87. If the rubidium-87 is part of a rock or mineral, then strontium-87 will remain trapped within the crystalline structure of the rock. The age of the rock dates back to the time when the rock solidified. Chemical analysis of the rock gives the amounts of \(^{87} \mathrm{Rb}\) and \(^{87}\) Sr. From these data, the fraction of \(^{87} \mathrm{Rb}\) that remains can be calculated. Analysis of a stony meteorite determined that \(1.8 \mathrm{mmol}\) of \(^{87} \mathrm{Rb}\) and \(1.6 \mathrm{mmol}\) of \(^{87} \mathrm{Sr}\) were present. Estimate the age of the meteorite. (Hint: The amount of \(^{87} \mathrm{Rb}\) at \(t_{0}\) is moles \(^{87} \mathrm{Rb}+\) moles \(^{87} \mathrm{Sr} .\))

Outline how nuclear reactions are carried out in the laboratory. Describe the artificial nuclear reactions used to make an element with an atomic number greater than 92.

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