/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 A 0.015 M solution of hydrogen c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 0.015 M solution of hydrogen cyanate, HOCN, has a pH of 2.67 (a) What is the hydronium ion concentration in the solution? (b) What is the ionization constant, \(K_{\alpha}\), for the acid?

Short Answer

Expert verified
(a) The hydronium ion concentration is approximately \(2.14 \times 10^{-3} \, M\). (b) The ionization constant \(K_a\) is approximately \(3.56 \times 10^{-4}\).

Step by step solution

01

Calculate Hydronium Ion Concentration

First, we need to find the hydronium ion concentration from the given pH value. The formula to find the hydronium ion concentration \( [H_3O^+] \) from pH is \[ [H_3O^+] = 10^{-pH} \]. Substitute the given pH value: \[ [H_3O^+] = 10^{-2.67} \].Using a calculator, \[ [H_3O^+] \approx 2.14 \times 10^{-3} \, M \].
02

Use Acid Dissociation Equation

The dissociation of HOCN in the solution is given by the equation:\[ \text{HOCN (aq)} \rightleftharpoons \text{H}^+ (\text{aq}) + \text{OCN}^- (\text{aq}) \]At equilibrium, \([H^+] = [OCN^-] = x \), where \( x \) is the concentration of ions dissociated.
03

Calculate Ionization Constant \(K_{a}\)

The acid dissociation constant \( K_a \) is calculated using the expression:\[ K_a = \frac{[H^+][OCN^-]}{[HOCN]} \]Since \( [H^+] = [OCN^-] = 2.14 \times 10^{-3} \) M and the initial concentration of HOCN is 0.015 M, the expression becomes:\[ K_a = \frac{(2.14 \times 10^{-3})^2}{0.015 - 2.14 \times 10^{-3}} \]Now calculate:\[ K_a = \frac{4.58 \times 10^{-6}}{0.01286} \approx 3.56 \times 10^{-4} \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydronium Ion Concentration
To understand the hydronium ion concentration in a solution, it is crucial to first know what a hydronium ion, \( [H_3O^+] \), is. This ion is formed when a proton \( (H^+) \) combines with a water molecule. In the context of acids, hydronium ions are essential as they essentially define the acidity of a solution. Calculating the hydronium ion concentration from the pH is straightforward. The pH is a measure of how acidic or basic a solution is, and it's calculated as the negative logarithm (base 10) of the hydronium ion concentration. Therefore, to find \( [H_3O^+] \) from pH, you'll use:- The formula: \( [H_3O^+] = 10^{-pH} \).- For a pH of 2.67, the calculation is \( [H_3O^+] = 10^{-2.67} \).- This typically requires a calculator, resulting in \( [H_3O^+] \approx 2.14 \times 10^{-3} \, M \).This simple calculation not only helps in identifying how acidic a solution is, but it also sets the foundation for further calculations like determining the ionization constant.
Ionization Constant
The ionization constant, especially for acids denoted as \( K_a \), is a crucial concept for understanding acid strength. It measures the extent to which an acid dissociates in water. A larger \( K_a \) value indicates a stronger acid, meaning it dissociates more completely.For hydrogen cyanate, HOCN, the dissociation can be written as:- \[\text{HOCN (aq)} \rightleftharpoons \text{H}^+ (\text{aq}) + \text{OCN}^- (\text{aq})\]- At equilibrium, the concentration of \( \text{H}^+ \) ions is equal to that of \( \text{OCN}^- \) ions, denoted by \( x \).The ionization constant \( K_a \) is calculated by:- \( K_a = \frac{[H^+][OCN^-]}{[HOCN]} \)- Given \( [H^+] = [OCN^-] = 2.14 \times 10^{-3} \) M and the initial \( [HOCN] = 0.015 \, M \), the calculation becomes: \( K_a = \frac{(2.14 \times 10^{-3})^2}{0.015 - 2.14 \times 10^{-3}} \).Finally, the result is approximately \( K_a \approx 3.56 \times 10^{-4} \), showing the degree to which HOCN dissociates into ions.
pH Calculation
Calculating the pH of a solution is a fundamental aspect of understanding its acidity or basicity. The term pH stands for "potential of hydrogen" and it represents the negative logarithm of the hydronium ion concentration.Here's how you calculate pH:
  • Use the formula: \( \text{pH} = -\log_{10} [H_3O^+] \).
  • In our given problem, if \( [H_3O^+] \approx 2.14 \times 10^{-3} \, M \), you’d calculate the pH by substituting this value into the formula.
To obtain the pH:- Use a scientific calculator or logarithm tables to find \( \text{pH} = -\log_{10} (2.14 \times 10^{-3}) \).- The result will confirm the pH provided in the problem, matching closely to 2.67.Understanding this calculation helps in a wide range of chemistry applications, from industrial synthesis to the biochemical processes within the human body.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A weak acid has a \(K_{\mathrm{a}}\) of \(6.5 \times 10^{-5} .\) What is the value of \(\mathrm{p} K_{\mathrm{a}}\) for the acid?

Decide whether each of the following substances should be classified as a Lewis acid or a Lewis base. (a) \(\mathrm{BCl}_{3}\) (Hint: Draw the electron dot structure.) (b) \(\mathrm{H}_{2} \mathrm{NNH}_{2},\) hydrazine (Hint: Draw the electron dot structure. (c) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (Hint: Draw the electron dot structure.)

Carbon monoxide forms complexes with low-valent metals. For example, \(\mathrm{Ni}(\mathrm{CO})_{4}\) and \(\mathrm{Fe}(\mathrm{CO})_{5}\) are well known. CO also forms complexes with the iron(II) ion in hemoglobin, which prevents the hemoglobin from acting in its normal way. Is CO a Lewis acid or a Lewis base?

A You have three solutions labeled \(A, B,\) and \(C .\) You know only that each contains a different cation-Na \(^{+}\) \(\mathrm{NH}_{4}^{+},\) or \(\mathrm{H}^{+}\). Each has an anion that does not contribute to the solution \(\mathrm{pH}\) (e.g., \(\mathrm{Cl}^{-}\) ). You also have two other solutions, Y and Z, each containing a different anion, \(\mathrm{Cl}^{-}\) or \(\mathrm{OH}^{-},\) with a cation that does not influence solution \(\mathrm{pH}\left(\text { e.g. }, \mathrm{K}^{+}\right) .\) If equal amounts of \(\mathrm{B}\) and \(\mathrm{Y}\) are mixed, the result is an acidic solution. Mixing A and Z gives a neutral solution, whereas \(\mathrm{B}\) and \(\mathrm{Z}\) give a basic solution. Identify the five unknown solutions. (Adapted from D. H. Barouch: Voyages in Conceptual Chemistry, Boston, Jones and Bartlett, \(1997 .)\) (TABLE CAN'T COPY)

Phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right),\) commonly called carbolic acid, is a weak organic acid. $$\begin{array}{c} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq}) \\ K_{\mathrm{a}}=1.3 \times 10^{-10} \end{array}$$ If you dissolve \(0.195 \mathrm{~g}\) of the acid in enough water to make \(125 \mathrm{~mL}\) of solution, what is the equilibrium hydronium ion concentration? What is the pH of the solution?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.