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Rank the following in order of increasing strength of intermolecular forces in the pure substances. Which exist as gases at \(25^{\circ} \mathrm{C}\) and 1 atm? (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\) (butane) (b) \(\mathrm{CH}_{3} \mathrm{OH}\) (methanol) (c) He

Short Answer

Expert verified
The order is He < CH3CH2CH2CH3 < CH3OH. He and CH3CH2CH2CH3 exist as gases at 25°C and 1 atm.

Step by step solution

01

Identify the Type of Intermolecular Forces Present

First, identify the types of intermolecular forces present in each substance. He (helium) is a noble gas and exhibits London dispersion forces. CH3CH2CH2CH3 (butane) is a nonpolar molecule and also exhibits London dispersion forces, but stronger than helium due to its larger size. CH3OH (methanol) is a polar molecule and can form hydrogen bonds, making its intermolecular forces stronger than both helium and butane.
02

Rank the Substances by Intermolecular Forces

Now that the intermolecular forces are identified, we can rank the substances by their strength. Helium, which only has weak London dispersion forces, has the weakest intermolecular forces. Butane, with stronger London dispersion forces due to its larger size, comes next. Methanol, which can form hydrogen bonds, has the strongest intermolecular forces of the three.
03

Consider the State of Each Substance at Given Conditions

At 25°C and 1 atm, determine which substances exist as gases. Helium, being a noble gas, naturally exists as a gas under these conditions. Butane with moderate dispersion forces also exists as a gas. Methanol, with strong hydrogen bonding, exists as a liquid at this temperature and pressure.
04

Final Ranking and Identification of Gases

Based on the analysis, the order of increasing strength of intermolecular forces is: He < CH3CH2CH2CH3 < CH3OH. The substances that exist as gases at 25°C and 1 atm are He and CH3CH2CH2CH3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

London Dispersion Forces
London dispersion forces are the weakest type of intermolecular forces. They exist between momentary dipoles that occur due to the movement of electrons in atoms and nonpolar molecules. Even though these forces are weak, they can add up to create noticeable effects in larger atoms or nonpolar molecules. This is why larger molecules, like butane (CH3CH2CH2CH3), have stronger dispersion forces compared to smaller atoms like helium.
Butane, for example, is a larger molecule than helium. It has more electrons, which can move around and create these temporary dipoles, leading to stronger dispersion forces. Despite being weak, London dispersion forces play a crucial role in determining the physical state and properties of molecules, especially nonpolar ones like butane and even the noble gas helium.
Hydrogen Bonding
Hydrogen bonding is significantly different from London dispersion forces. It is a much stronger type of intermolecular force. Occurring between a hydrogen atom directly bonded to electronegative atoms such as oxygen, nitrogen, or fluorine, hydrogen bonds create strong attractions between molecules.
Methanol (CH3OH) can form hydrogen bonds because of its OH group. The oxygen atom is highly electronegative and creates a strong attraction with hydrogen atoms from neighboring methanol molecules.
This strong intermolecular force is why methanol has a higher boiling point compared to substances like butane and helium. Unlike the weak and temporary nature of dispersion forces, hydrogen bonds contribute to methanol existing as a liquid at room temperature.
Physical State of Substances
The physical state of a substance at a given temperature and pressure depends largely on the kind of intermolecular forces present. Substances with stronger forces, like hydrogen bonds, tend to be solids or liquids at room temperature, whereas substances with weaker forces, like London dispersion forces, can be gases.
At 25°C and 1 atm, helium is a gas because it only experiences weak London dispersion forces. Butane, while having stronger dispersion forces than helium, is also a gas because these forces are not strong enough to hold the molecules together in a liquid state.
Methanol, on the other hand, exists as a liquid due to hydrogen bonding, which effectively keeps its molecules closely packed, overcoming any tendency for them to spread out into a gaseous state. Understanding the impact these forces have on physical states can help predict and explain the behaviors of different substances under various conditions.

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Most popular questions from this chapter

What type of intermolecular force must be overcome in converting each of the following from a liquid to a gas? (a) liquid \(\mathrm{O}_{2}\) (b) mercury (c) \(\mathrm{CH}_{3} \mathrm{I}\) (methyl iodide) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (ethanol)

Two identical swimming pools are filled with uniform spheres of ice packed as closely as possible. The spheres in the first pool are the size of grains of sand; those in the second pool are the size of oranges. The ice in both pools melts. In which pool, if either, will the water level be higher? (Ignore any differences in filling space at the planes next to the walls and bottom.)

The specific heat capacity of silver is \(0.235 \mathrm{J} / \mathrm{g} \cdot \mathrm{K}\). Its melting point is \(962^{\circ} \mathrm{C},\) and its heat of fusion is \(11.3 \mathrm{kJ} / \mathrm{mol}\) What quantity of heat, in joules, is required to change \(5.00 \mathrm{g}\) of silver from a solid at \(25^{\circ} \mathrm{C}\) to a liquid at \(962^{\circ} \mathrm{C} ?\)

Benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), is an organic liquid that freezes at \(5.5^{\circ} \mathrm{C}\) (see Figure \(13.1)\) to form beautiful, feather-like crystals. How much heat is evolved when 15.5 g of benzene freezes at \(5.5^{\circ} \mathrm{C} ?\) (The heat of fusion of benzene is \(9.95 \mathrm{kJ} / \mathrm{mol}\).) If the 15.5 -g sample is remelted, again at \(5.5^{\circ} \mathrm{C},\) what quantity of heat is required to convert it to a liquid?

What types of intermolecular forces are important in the liquid phase of (a) \(\mathrm{C}_{2} \mathrm{H}_{6}\) and (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH} ?\)

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