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You have two pressure-proof steel cylinders of equal volume, one containing \(1.0 \mathrm{kg}\) of \(\mathrm{CO}\) and the other containing \(1.0 \mathrm{kg}\) of acetylenc, \(\mathrm{C}_{2} \mathrm{H}_{2}\) (a) In which cylinder is the pressure greater at \(25^{\circ} \mathrm{C} ?\) (b) Which cylinder contains the greater number of molecules?

Short Answer

Expert verified
(a) Acetylene cylinder has greater pressure. (b) Acetylene cylinder has more molecules.

Step by step solution

01

Calculate Molar Mass of CO and C2H2

First, we need to determine the molar mass for each gas. The molar mass of carbon monoxide (CO) is calculated by adding the atomic mass of carbon (12.01 g/mol) and oxygen (16.00 g/mol), which gives us: \[ \text{Molar Mass of CO} = 12.01 + 16.00 = 28.01 \ \text{g/mol} \]For acetylene (C2H2), the molar mass is given by: \[ \text{Molar Mass of C}_{2}\text{H}_{2} = 2(12.01) + 2(1.008) = 26.036 \ \text{g/mol} \]
02

Determine the Number of Moles

Using the known weights of the gases (1.0 kg = 1000 g) and their respective molar masses calculated above, we calculate the number of moles of each gas:For CO:\[ \text{Number of moles of CO} = \frac{1000}{28.01} = 35.7 \ \text{moles} \]For C2H2:\[ \text{Number of moles of C}_{2}\text{H}_{2} = \frac{1000}{26.036} = 38.4 \ \text{moles} \]
03

Compare the Pressures

Both gases are in equal volumes at the same temperature. According to the ideal gas law \(PV = nRT\), since the volumes (V) and the temperature (T) remain constant, and assuming R is a constant, the pressure (P) will vary with the number of moles (n). Hence, the cylinder with more moles will have greater pressure.Since acetylene has more moles (38.4) compared to CO (35.7), the pressure in the acetylene cylinder is greater.
04

Count the Molecules

To find which cylinder contains the greater number of molecules, we need to use Avogadro's number (\(6.022 \times 10^{23}\) molecules/mol).Number of molecules in CO:\[ 35.7 \times 6.022 \times 10^{23} = 2.15 \times 10^{25} \ \text{molecules} \]Number of molecules in C2H2:\[ 38.4 \times 6.022 \times 10^{23} = 2.31 \times 10^{25} \ \text{molecules} \]Thus, the cylinder with acetylene has a greater number of molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
The molar mass of a substance is central to understanding chemical quantities. It is the mass of one mole of molecules or atoms. This is expressed in grams per mole (g/mol). The molar mass is obtained by summing the atomic mass units of all the atoms present in a molecular formula.

For example, to find the molar mass of carbon monoxide (CO), we add the atomic mass of carbon (12.01 g/mol) with oxygen (16.00 g/mol), giving us a molar mass of 28.01 g/mol for CO. Similarly, for acetylene (Câ‚‚Hâ‚‚), it involves summing the masses of its atoms: two carbon atoms and two hydrogen atoms. Thus, its molar mass is 26.036 g/mol.

This molar mass is crucial when calculating the number of moles, which helps us translate mass into a count of entities like molecules, enabling stoichiometric calculations. Understanding molar mass is foundational in comparing the quantities of different substances in chemical reactions.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry, which helps us to relate the pressure, volume, temperature, and number of moles of a gas. It is expressed by the equation: \[ PV = nRT \]where:
  • P is the pressure
  • V is the volume
  • n is the number of moles
  • R is the universal gas constant
  • T is the temperature in Kelvin
In this law, if any three of these variables are known, the fourth can be calculated.

For the gases in our cylinders, because they are at the same temperature and volume, the pressure becomes directly proportional to the number of moles. Hence, more moles mean higher pressure due to greater particle collisions within the same volume. This concept helps us determine why the acetylene cylinder has greater pressure than that containing carbon monoxide when both contain the same mass of gas.
Avogadro's Number
Avogadro's Number is a key concept for understanding the amount of substance in chemistry. It is the number of entities (usually atoms or molecules) in one mole of a substance, specifically: \[ 6.022 imes 10^{23} \] entities/mol.

This means one mole of any substance contains this vast number of particles, whether it's atoms in an element or molecules in a compound. This constant is essential for converting moles into an actual number of particles.

In our example problems, even though the mass of the gases is the same, converting to moles and then using Avogadro's Number allows us to determine which cylinder holds more molecules. By multiplying the number of moles found for each gas by Avogadro's Number, we see the acetylene cylinder holds more molecules than the carbon monoxide cylinder, because it has more moles. This is a wonderful illustration of Avogadro's principle that equal volumes of gases (at the same temperature and pressure) contain an equal number of molecules.

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Most popular questions from this chapter

If you have a sample of water in a closed container, some of the water will evaporate until the pressure of the water vapor, at \(25^{\circ} \mathrm{C},\) is \(23.8 \mathrm{mm}\) Hg. How many molecules of water per cubic centimeter exist in the vapor phase?

A balloon holds \(30.0 \mathrm{kg}\) of helium. What is the volume of the balloon if the final pressure is 1.20 atm and the temperature is \(22^{\circ} \mathrm{C} ?\)

Silane, \(\operatorname{SiH}_{4},\) reacts with \(\mathrm{O}_{2}\) to give silicon dioxide and water: $$ \sin _{4}(g)+2 \mathbf{O}_{2}(g) \longrightarrow \operatorname{SiO}_{2}(s)+2 \mathbf{H}_{2} \mathbf{O}(\ell) $$ A \(5.20-\mathrm{L}\) sample of \(\mathrm{SiH}_{4}\) gas at \(356 \mathrm{mm}\) Hg pressure and \(25^{\circ} \mathrm{C}\) is allowed to react with \(\mathrm{O}_{2}\) gas. What volume of \(\mathrm{O}_{2}\) gas, in liters, is required for complete reaction if the oxygen has a pressure of \(425 \mathrm{mm} \mathrm{Hg}\) at \(25^{\circ} \mathrm{C} ?\)

\(\mathrm{Ni}(\mathrm{CO})_{4}\) can be made by reacting finely divided nickel with gaseous CO. If you have \(\mathrm{CO}\) in a \(1.50-\mathrm{L}\). flask at a pressure of \(418 \mathrm{mm}\) Hg at \(25.0^{\circ} \mathrm{C},\) along with \(0.450 \mathrm{g}\) of \(\mathrm{Ni}\) powder, what is the theoretical yield of \(\mathrm{Ni}(\mathrm{CO})_{4} ?\)

You have a \(550-\mathrm{ml}\). tank of gas with a pressure of 1.56 atm at \(24^{\circ} \mathrm{C}\). You thought the gas was pure carbon monoxide gas, \(\mathrm{CO}\), but you later found it was contaminated by small quantities of gaseous \(\mathrm{CO}_{2}\) and \(\mathrm{O}_{2}\). Analysis shows that the tank pressure is 1.34 atm (at \(24^{-} \mathrm{C}\) ) if the \(\mathrm{CO}_{2}\) is removed. Another experiment shows that \(0.0870 \mathrm{~g}\) of \(\mathrm{O}_{2}\) can be removed chemically. What are the masses of \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\) in the tank, and what is the partial pressure of each of the three gases at \(25^{\circ} \mathrm{C}\) ?

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