Chapter 11: Problem 89
Identify the reaction products and write an equation for the following reactions of \(\mathrm{CH}_{2}=\mathrm{CHCH}_{2} \mathrm{OH}\) (a) \(\mathrm{H}_{2}\) (hydrogenation, in the presence of a catalyst) (b) oxidation (excess oxidizing agent) (c) addition polymerization (d) ester formation, using acetic acid
Short Answer
Step by step solution
Hydrogenation Reaction
Oxidation Reaction
Addition Polymerization
Ester Formation Reaction
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hydrogenation
In the given reaction, (\(\mathrm{CH}_2=\mathrm{CHCH}_2\mathrm{OH}\)) undergoes hydrogenation in the presence of a catalyst. The catalyst, often nickel (Ni), aids in breaking the double bond.
- The double bond between the carbons is broken.
- Hydrogen atoms fill the open spots in the molecule.
Oxidation of Alcohols
- The alcohol is first converted to an aldehyde.
- Further oxidation converts the aldehyde into a carboxylic acid.
- First, \(\mathrm{CH}_2=\mathrm{CHCH}_2\mathrm{OH}\) becomes \(\mathrm{CH}_2=\mathrm{CHCHO}\) (an aldehyde).
- Then, further oxidation gives us acrylic acid, \(\mathrm{CH}_2=\mathrm{CHCOOH}\).
Addition Polymerization
- The double bonds in the monomers open up during the reaction.
- Monomers link together forming long, repeating chains.
Esterification
- The hydroxyl group (\(\mathrm{OH}\)) from the alcohol and the hydrogen from the acid's carboxyl group (\(\mathrm{COOH}\)) bond to form water.
- The remaining acid and alcohol components join to form an ester.