/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 81 You are asked to calibrate a spe... [FREE SOLUTION] | 91Ó°ÊÓ

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You are asked to calibrate a spectrophotometer in the laboratory and collect the following data. Plot the data with concentration on the \(x\) -axis and absorbance on the \(y\) -axis. Draw the best straight line using the points on the graph (or do a least-squares or linear regression analysis using a computer program) and then write the equation for the resulting straight line. What is the slope of the line? What is the concentration when the absorbance is \(0.635 ?\) $$\begin{array}{ll} \hline \text { Concentration }(\mathrm{M}) & \text { Absorbance } \\ \hline 0.00 & 0.00 \\ 1.029 \times 10^{-3} & 0.257 \\ 2.058 \times 10^{-3} & 0.518 \\ 3.087 \times 10^{-3} & 0.771 \\ 4.116 \times 10^{-3} & 1.021 \\ \hline \end{array}$$

Short Answer

Expert verified
Slope is 0.248. Concentration for absorbance 0.635 is approximately 2.56 × 10^{-3} M.

Step by step solution

01

Understanding the Task

We need to plot concentration vs. absorbance data, find the line of best fit, and determine the slope and intercept of the line. Then, use the equation to find the concentration for a given absorbance.
02

Plotting the Data

Plot concentration ( M) on the x-axis and absorbance on the y-axis. The data points are (0, 0), (1.029×10^{-3}, 0.257), (2.058×10^{-3}, 0.518), (3.087×10^{-3}, 0.771), (4.116×10^{-3}, 1.021).
03

Drawing the Best Fit Line

Use a linear regression tool to draw the best fit line through the data points. You may also use software like Excel for precise fitting.
04

Finding the Line Equation

The regression analysis will provide a line equation in the form \( y = mx + c \). Typically, software will output \( m \) (slope) and \( c \) (y-intercept).
05

Calculating the Slope and Intercept

From linear regression analysis, the slope \( m \) is found to be approximately 0.248, and the intercept \( c \) is approximately 0 (close to zero).
06

Using the Line Equation

The line equation becomes \( y = 0.248x \). Given absorbance \( y = 0.635 \), we solve for \( x \):
07

Solving for Concentration

Set 0.635 = 0.248x. Solve for \( x \) by dividing both sides by 0.248: \( x = \frac{0.635}{0.248} \approx 2.56 \times 10^{-3}\ M \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression Analysis
Linear regression analysis is a powerful statistical tool used to find the relationship between two quantitative variables. In the context of spectrophotometer calibration, it helps determine the best fit line that shows how absorbance changes with concentration.

To perform a linear regression, one needs to plot the given data points onto a graph and calculate the line that minimizes the distance from all data points to the line. This line is commonly called the line of best fit.

Using software, like Excel, or statistical calculators, you can carry out linear regression analysis efficiently. The tool calculates the slope (\(m\)) and the intercept (\(c\)) of the line, yielding an equation in the form \(y = mx + c\). This equation helps predict the absorbance for unknown concentrations, providing a straightforward method to interpret spectrophotometer data.
Absorbance Measurement
Absorbance measurement is essential in determining how much light a solution absorbs at a specific wavelength. In the spectrophotometer calibration, you measure absorbance for solutions of known concentrations to establish a correlation.

Each data point on our graph of concentration versus absorbance represents a solution's visually measured absorbance. By plotting these points, the aim is to see how absorbance increases as concentration increases. Generally, this relationship is linear, meaning the plot should closely form a straight line.

Since the initial concentration is zero, the absorbance should naturally start at zero. As concentration rises, absorbance data points will climb, showing the trend that will aid in forming the best fit line through our key data points.
Concentration Determination
Determining the concentration of an unknown sample using a spectrophotometer involves using the equation derived from linear regression. With the established line equation, concentration determination becomes a calculation.

For instance, if we know an absorbance value and wish to find the corresponding concentration, we rearrange the line equation \(y = 0.248x\) to solve for \(x\) (concentration). Using \(0.635\) as the absorbance, you replace \(y\) and solve: \(x = \frac{0.635}{0.248}\).

This gives you the concentration \(x\), which is approximately\(2.56 \times 10^{-3}M\). Utilizing this method ensures that even if the samples vary in absorbance, their concentration can be accurately calculated.

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Most popular questions from this chapter

A piece of turquoise is a blue-green solid, and has a density of \(2.65 \mathrm{g} / \mathrm{cm}^{3}\) and a mass of \(2.5 \mathrm{g}\) (a) Which of these observations are qualitative and which are quantitative? (b) Which of these observations are extensive and which are intensive? (c) What is the volume of the piece of turquoise?

Ethylene glycol, \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{2},\) is an ingredient of automobile antifreeze. Its density is \(1.11 \mathrm{g} / \mathrm{cm}^{3}\) at \(20^{\circ} \mathrm{C}\). If you need exactly \(500 .\) mL of this liquid, what mass of the compound, in grams, is required?

Hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}, d=0.766 \mathrm{g} / \mathrm{cm}^{3}\right),\) perfluorohexane \(\left(\mathrm{C}_{6} \mathrm{F}_{14}, d=1.669 \mathrm{g} / \mathrm{cm}^{3}\right),\) and water are immiscible liq- uids; that is, they do not dissolve in one another. You place 10 mL of each liquid in a graduated cylinder, along with pieces of high-density polyethylene (HDPE, \(d=\) \(\left.\left.0.97 \mathrm{g} / \mathrm{cm}^{3}\right), \text { polyvinyl chloride (PVC, } d=1.36 \mathrm{g} / \mathrm{cm}^{3}\right)\) and Teflon (density \(=2.3 \mathrm{g} / \mathrm{cm}^{3}\) ). None of these common plastics dissolve in these liquids. Describe what you expect to see.

When you heat popcorn, it pops because it loses water explosively. Assume a kernel of corn, with a mass of \(0.125 \mathrm{g},\) has a mass of only \(0.106 \mathrm{g}\) after popping. (a) What percentage of its mass did the kernel lose on popping? (b) Popcorn is sold by the pound in the United States. Using \(0.125 \mathrm{g}\) as the average mass of a popcorn kernel, how many kernels are there in a pound of popcorn? \((1 \mathrm{lb}=453.6 \mathrm{g} .)\)

A red blood cell has a diameter of \(7.5 \mu \mathrm{m}\) (micrometers). What is this dimension in (a) meters, (b) nanometers, and (c) picometers?

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