/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Milk in a glass bottle was place... [FREE SOLUTION] | 91Ó°ÊÓ

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Milk in a glass bottle was placed in the freezer compartment of a refrigerator overnight. By morning a column of frozen milk emerged from the bottle. Explain this observation.(IMAGE CAN'T COPY)

Short Answer

Expert verified
Milk expands when frozen, forming a column as it has nowhere else to expand except upwards.

Step by step solution

01

Understanding Freezing Expansion

When water freezes, it expands. In this case, milk contains a significant amount of water, and as the milk freezes, the water molecules form a structured lattice that occupies more space than the liquid form.
02

Observing the Bottle Constraint

The original volume of liquid milk fills the bottle, but as it freezes and expands, the rigid structure of the glass bottle prevents lateral expansion.
03

Noticing Vertical Expansion

Because the glass bottle restricts lateral expansion due to its rigid sides, the expansion occurs in the direction of least resistance, which is upward. Thus, the frozen milk forms a column above the bottle.
04

Explaining the Frozen Milk Column

The column of frozen milk emerges beyond the top of the bottle because frozen milk (primarily the water component) expands. With no room to expand sideways due to the bottle's walls, the expansion forces the milk upwards.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Milk
Milk is a complex liquid with a multitude of nutrients and components. It is primarily composed of water, but it also contains fats, proteins, and carbohydrates, such as lactose. In fact, milk is around 87% water, which plays a significant role during any phase change processes.

The presence of water is crucial in understanding why milk behaves similarly to pure water when freezing. Since water expands upon freezing, this property heavily influences the physical changes observed in milk when subjected to low temperatures. Additionally, the rigid structure of proteins and fats may contribute to the semi-solid form observed when milk is frozen.
Phase Changes
Phase changes refer to the transitions between different states of matter: solid, liquid, and gas. In the context of milk freezing, this involves the transition from a liquid state to a solid state. During this process, the temperature of the milk decreases until it reaches its freezing point, at which molecules begin to form a solid structure.

The transition is mainly dictated by the water content in milk, as water freezes at 0°C (32°F). As the temperature drops, water molecules slow down and arrange into a crystalline structure, resulting in expansion. The proteins and fats within milk will also partially crystallize, but the primary contributor to phase change, and subsequent expansion, is the water content.
Freezing Process
The freezing process is an intriguing phenomenon, particularly because it involves an unexpected behavior—expansion rather than contraction. Unlike most substances, water expands when it freezes due to its hydrogen bonding creating an open hexagonal lattice. In milk, the freezing process is dominated by water's properties, causing the overall volume to increase.

The glass bottle containing the milk acts as a boundary restrictant, confining the lateral expansion and forcing the frozen milk to expand vertically. The lack of space for expansion allows for a visually clear observation of this process, as seen with the creation of a frozen column of milk emerging from the bottle.
Observation of Physical Changes
Observing physical changes like the expansion and solidification of milk can provide us with a clear understanding of fundamental scientific principles. As milk cools and begins the phase change process, you can notice these transformative changes.

Initially, the milk's surface may appear simply colder and slightly more viscous. However, as freezing progresses, the structured crystallization of water content becomes prominent, leading to an obvious increase in volume.
  • The expansion creates upward movement due to spatial constraints posed by the rigid bottle walls.
  • The buoyancy and force of this expansion result in observable protrusion beyond the bottle's opening.
This showcases a fascinating interplay between materials and the forces at play during phase changes.

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Most popular questions from this chapter

A 26 -meter tall statue of Buddha in Tibet is covered with 279 kg of gold. If the gold was applied to a thickness of \(0.0015 \mathrm{mm},\) what surface area is covered (in square meters)? (Gold density \(=19.3 \mathrm{g} / \mathrm{cm}^{3} .\) )

The substances listed below are clear liquids. You are asked to identify an unknown liquid that is known to be one of these liquids. You pipette a 3.50 -mL sample into a beaker. The empty beaker had a mass of \(12.20 \mathrm{g}\), and the beaker plus the liquid weighed \(16.08 \mathrm{g}\) $$\begin{array}{ll} \hline \text { Substance } & \text { Known Density at } 25^{\circ} \mathrm{C}\left(\mathrm{g} / \mathrm{cm}^{3}\right) \\ \hline \text { Ethylene glycol } & 1.1088 \text { (the major component of antifreeze) } \\ \text { Water } & 0.9997 \\ \text { Ethanol } & 0.7893 \text { (the alcohol in alcoholic beverages) } \\ \text { Acetic acid } & 1.0492 \text { (the active component of vinegar) } \\ \text { Glycerol } & 1.2613 \text { (a solvent, used in home care } \\ \text { products) } \\ \hline \end{array}$$ (a) Calculate the density and identify the unknown. (b) If you were able to measure the volume to only two significant figures (that is, \(3.5 \mathrm{mL},\) not \(3.50 \mathrm{mL}\) ), will the results be sufficiently accurate to identify the unknown? Explain.

A The density of a single, small crystal can be determined by the flotation method. This method is based on the idea that if a crystal and a liquid have precisely the same density, the crystal will hang suspended in the liquid. A crystal that is more dense will sink; one that is less dense will float. If the crystal neither sinks nor floats, then the density of the crystal equals the density of the liquid. Generally, mixtures of liquids are used to get the proper density. Chlorocarbons and bromocarbons (see the list below) are often the liquids of choice. If the two liquids are similar, then volumes are usually additive and the density of the mixture relates directly to composition. (An example: \(1.0 \mathrm{mL}\) of \(\mathrm{CHCl}_{3}, d=1.4832 \mathrm{g} / \mathrm{mL},\) and 1.0 mL of \(\mathrm{CCl}_{4}, d=1.5940 \mathrm{g} / \mathrm{mL},\) when mixed, give \(2.0 \mathrm{mL}\) of a mixture with a density of \(1.5386 \mathrm{g} / \mathrm{mL} .\) The density of the mixture is the average of the values of the two individual components.) The problem: A small crystal of silicon, germanium, tin, or lead (Group 4A in the periodic table) will hang suspended in a mixture made of \(61.18 \%\) (by volume) \(\mathrm{CH}\) IBr \(_{3}\) and \(38.82 \%\) (by volume) \(\mathrm{CHCl}_{3} .\) Calculate the density and identify the element. (You will have to look up the values of the density of the elements in a manual such as the The Handbook of Chemistry and Physics in the library or in a World Wide Web site such as WebElements at, www.webelements.com.) $$\begin{array}{llll} \hline \text { Liquid } & \text { Density }(\mathrm{g} / \mathrm{mL}) & \text { Liquid } & \text { Density }(\mathrm{g} / \mathrm{mL}) \\ \hline \mathrm{CH}_{2} \mathrm{Cl}_{2} & 1.3266 & \mathrm{CH}_{2} \mathrm{Br}_{2} & 2.4970 \\ \mathrm{CH} \mathrm{Cl}_{3} & 1.4832 & \mathrm{CHBr}_{3} & 2.8899 \\ \mathrm{CCl}_{4} & 1.5940 & \mathrm{CBr}_{4} & 2.9609 \\ \hline \end{array}$$

Diamond has a density of \(3.513 \mathrm{g} / \mathrm{cm}^{3} .\) The mass of diamonds is often measured in "carats," where 1 carat equals \(0.200 \mathrm{g} .\) What is the volume (in cubic centimeters) of a 1.50 -carat diamond?

A The smallest repeating unit of a crystal of common salt is a cube (called a unit cell) with an edge length of \(0.563 \mathrm{nm}\). (a) What is the volume of this cube in cubic nanometers? In cubic centimeters? (b) The density of \(\mathrm{NaCl}\) is \(2.17 \mathrm{g} / \mathrm{cm}^{3} .\) What is the mass of this smallest repeating unit ("unit cell")? (c) Each repeating unit is composed of four NaCl "molecules." What is the mass of one NaCl molecule? (IMAGE CAN'T COPY)

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