Chapter 9: Problem 60
Consider the three fluorides \(\mathrm{BF}_{4}, \mathrm{SiF}_{4},\) and \(\mathrm{SF}_{4}\) (a) Identify a molecule that is isoelectronic with \(\mathrm{BF}_{4}\) (b) Are \(\operatorname{sir}_{4}\) and \(\mathrm{SF}_{4}\) isoelectronic? (c) What is the hybridization of the central atom in \(\mathrm{BF}_{4}^{-}\) and \(\mathrm{SiF}_{4} ?\)
Short Answer
Step by step solution
Understanding Isoelectronic Species
Calculate Electrons in \(\mathrm{BF}_4^-\)
Find Isoelectronic Molecule to \(\mathrm{BF}_4^-\)
Verify \(\mathrm{SiF}_4\) and \(\mathrm{SF}_4\) Electron Counts
Determine Isoelectronic State Between \(\mathrm{SiF}_4\) and \(\mathrm{SF}_4\)
Determine Hybridization of Central Atom in \(\mathrm{BF}_4^-\)
Determine Hybridization of Central Atom in \(\mathrm{SiF}_4\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Structure
The molecular structure of a compound can be predicted using its hybridization, electron pair geometry, and molecular geometry. In the case of tetrafluoroborate ion (\(\mathrm{BF}_4^-\)), silicon tetrafluoride (\(\mathrm{SiF}_4\)), and sulfur tetrafluoride (\(\mathrm{SF}_4\)), the molecular structures are primarily defined by the arrangement around their central atom.
- For \(\mathrm{BF}_4^-\) and \(\mathrm{SiF}_4\), both have a tetrahedral structure. This results from the presence of four bond pairs around the central atom, creating a symmetric and stable shape. - In contrast, \(\mathrm{SF}_4\) deviates slightly from the perfect tetrahedral geometry due to the presence of a lone pair on sulfur, resulting in a see-saw shape.
Electron Count
To determine if two molecules are isoelectronic, one simply needs to add up their valence electrons. Here's how it looks for some molecules:
- For \(\mathrm{BF}_4^-\), there are: 5 electrons from B + 28 from the four F atoms + 1 extra from the negative charge, totalling 32.
- Similarly, both \(\mathrm{SiF}_4\) and \(\mathrm{SF}_4\) have 42 electrons. Silicon in \(\mathrm{SiF}_4\) provides 14, while sulfur in \(\mathrm{SF}_4\) offers 16 electrons, with each contributing the electrons from their fluorines, leading to a total of 42.
Hybridization
Overall, the type of hybridization determines the angles between bonds and the overall shape. Specifically:
- For \(\mathrm{BF}_4^-\), the boron atom undergoes \(sp^3\) hybridization. This occurs due to four equivalent bonds formed with fluorine atoms, where these orbitals are symmetrically distributed creating a tetrahedral shape.
- The \(\mathrm{SiF}_4\) molecule also utilizes \(sp^3\) hybridization at the silicon atom. Like boron, silicon uses all its orbitals to bond to four fluorines, leading to a tetrahedral configuration.
- Hybridization also explains complex shapes like the \(\mathrm{SF}_4\) molecule, where the presence of a lone pair on the sulfur modifies it from a perfect tetrahedral to a see-saw shape, involving \(sp^3d\) hybridization.