/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Explain why (a) \(\mathrm{XeF}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why (a) \(\mathrm{XeF}_{2}\) has a linear molecular structure and not a bent one. (b) \(\mathrm{ClF}_{3}\) has a T-shaped structure and not a trigonal-planar one.

Short Answer

Expert verified
(a) XeF2 has a linear structure due to three lone pairs that align the two fluorine atoms linearly. (b) ClF3 has a T-shaped structure due to five regions of electron density, where two lone pairs cause the remaining bonds to form a T shape.

Step by step solution

01

Understand the Molecular Geometry Concept

Molecular geometry is determined by the number of bonding pairs and lone pairs of electrons around the central atom. VSEPR (Valence Shell Electron Pair Repulsion) theory states that electron pairs will arrange themselves to be as far apart as possible.
02

Analyze XeF2 Structure

Xenon difluoride ( XeF_2 ) has a total of 22 valence electrons. Xenon is the central atom with 5 electron pairs: 2 bonding pairs with fluorine atoms and 3 lone pairs. According to VSEPR theory, 5 electron pairs arrange into a trigonal bipyramidal geometry. The 3 lone pairs are placed in the equatorial positions to minimize repulsion, resulting in a linear molecular shape for the Xe-F bonds.
03

Explain Linear Shape of XeF2

The linear shape arises because the 3 lone pairs in equatorial positions balance each other out, allowing the 2 fluorine atoms to be 180° apart. Thus, the molecule maintains its linear structure.
04

Analyze ClF3 Structure

Chlorine trifluoride ( ClF_3 ) has a total of 28 valence electrons. Chlorine is the central atom with 5 electron pairs: 3 bonding pairs with fluorine atoms and 2 lone pairs. According to VSEPR theory, these 5 pairs arrange into a trigonal bipyramidal geometry.
05

Explain T-shaped Shape of ClF3

The presence of two lone pairs, located in the equatorial plane, causes the three bond pairs with fluorines in axial and a single equatorial position. Electrons in lone pairs exert more repulsion than bonded electrons, resulting in a T-shaped molecular geometry.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry is a core concept in chemistry that describes the three-dimensional arrangement of atoms in a molecule. This structure is determined by the electron pairs surrounding a molecule's central atom. The Valence Shell Electron Pair Repulsion (VSEPR) theory is central to understanding molecular geometry. According to VSEPR theory, electron pairs prefer to be as far apart as possible to minimize repulsive forces between them. This arrangement affects the shape and angles between bonds of a molecule. For example, molecules could take on shapes such as linear, bent, trigonal planar, or tetrahedral.

Molecular geometry is pivotal because it influences the chemical properties and reactivity of a substance. By understanding how bonding and lone pairs interact within this framework, one can predict and rationalize the shapes of more complex molecules. Researchers and students can thus use these principles to explore molecules like xenon difluoride and chlorine trifluoride.
Xenon Difluoride
Xenon difluoride (XeFâ‚‚) is an intriguing molecule in terms of molecular geometry. It serves as a classic example of how VSEPR theory governs structure formation. Xenon acts as the central atom, and it is surrounded by five regions of electron density: two bonding pairs forming bonds with fluorine atoms, and three lone pairs of electrons.

According to VSEPR theory, these five regions initially adopt a trigonal bipyramidal layout. However, the three lone pairs occupy the equatorial positions due to less steric hindrance, as they prefer to be around the center to minimize repulsion. This geometrical arrangement causes the bonded fluorine atoms to position themselves in an opposite, straight-line formation. Hence, the molecule adopts a linear geometry with bond angles of 180°. This clever arrangement allows xenon difluoride, despite having lone pairs, to maintain a linear shape, highlighting the insights VSEPR provides in predicting molecular shapes.
Chlorine Trifluoride
Chlorine trifluoride (ClF₃) showcases another interesting case study for molecular geometry through the lens of VSEPR theory. In this molecule, chlorine serves as the central atom with five regions of electron density—three bonding pairs and two lone pairs. Similar to XeF₂, these regions arrange into a trigonal bipyramidal shape initially.

However, due to the presence of two lone pairs, the molecule does not remain in this shape. Lone pairs tend to exert more repulsion than bonding pairs. Consequently, the lone pairs situate themselves in equatorial positions to minimize repulsion, leading to a rearranged geometry. This results in the three flourine atoms existing at the actual and equatorial position, forming a T-shape. Such structural rearrangement is why ClF₃ does not form a planar triangular shape, but rather a T-shaped one, emphasizing the significance of lone pairs in determining molecular structure.
Electron Pair Repulsion
Electron pair repulsion forms the crux of VSEPR theory and is crucial for understanding molecular geometries. Essentially, electron pairs — whether in bonds or as lone pairs — repel each other. This repulsive force is the driving reason behind particular molecular shapes and arrangements.

Different types of electron pairs have varying levels of repulsion. For instance, lone pairs exhibit stronger repulsion than bonded pairs, often due to their greater electron density. This principle helps explain why molecules like XeF₂ and ClF₃ adopt linear and T-shaped structures, respectively.
  • Lone pairs will push bonded pairs closer together, affecting bond angles and shapes.
  • The spatial distribution of these pairs leads to the distinction among bent, trigonal, or linear shapes.
Understanding electron pair repulsion allows us to predict how a molecule might react or interact with other molecules, making it a fundamental aspect of molecular chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw a Lewis structure for each of the following molecules: (a) methanol, \(\mathrm{CH}_{3} \mathrm{OH}\) (b) vinyl chloride, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCl}\), the molecule from which PVC plastics are made (c) acrylonitrile, \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCN}\), the molecule from which materials such as Orlon are made EQUATION CANT COPY

The cyanate ion, OCN \(^{-}\), has the least electronegative atom, \(\mathrm{C},\) in the center. The unstable fulminate ion, \(\mathrm{CNO}^{-},\) has the same molecular formula, but the \(N\) atom is in the center. (a) Draw the three possible resonance structures of \(\mathrm{CNO}^{-}\) (b) On the basis of formal charges, decide on the resonance structure with the most reasonable distribution of charge. (c) Mercury fulminate is so unstable it is used in blasting caps for dynamite. Can you offer an explanation for this instability? (Hint: Are the formal charges in any resonance structure reasonable in view of the relative electronegativities of the atoms?)

Consider the following molecules: (a) \(\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{CO}_{2}\) (e) \(\mathrm{CCl}_{4}\) (b) \(\mathrm{NH}_{3}\) (d) CIF (i) In which compound are the bonds most polar? (ii) Which compounds in the list are not polar? (iii) Which atom in ClF is more negatively charged?

Which of the following molecules is(are) polar? For each polar molecule, indicate the direction of polarity-that is, which is the negative end, and which is the positive end of the molecule. (a) \(\mathrm{BeCl}_{2}\) (b) \(\mathrm{HBF}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{Cl}\) (d) \(\mathrm{SO}_{3}\)

For elements in Groups \(4 \mathrm{A}-7 \mathrm{A}\) of the periodic table, give the number of bonds an element is expected to form (in an uncharged molecule) if it obeys the octet rule.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.