/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 What does the term standard stat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What does the term standard state mean? What are the standard states of the following substances at \(298 \mathrm{K}: \mathrm{H}_{2} \mathrm{O}, \mathrm{NaCl}, \mathrm{Hg}, \mathrm{CH}_{4} ?\)

Short Answer

Expert verified
Standard states at 298 K are: H2O (liquid), NaCl (solid), Hg (liquid), CH4 (gas).

Step by step solution

01

Define 'Standard State'

The standard state of a substance is a reference point used to calculate its properties under specified conditions. It typically refers to the state of a material at a pressure of 1 bar (about 1 atmosphere) and at a specified temperature, usually 298 K (25°C), but for gases at their pressure of 1 bar."
02

Determine Standard State for Water ( H2O )

At 298 K, the standard state of water is the liquid phase. This is because water is a liquid at room temperature (about 298 K), which aligns with the definition of its standard state.
03

Determine Standard State for Sodium Chloride ( NaCl )

Sodium chloride is typically found in the solid state at 298 K, so its standard state is solid. This is also true because, at room temperature, NaCl forms a crystalline solid known as table salt.
04

Determine Standard State for Mercury ( Hg )

Mercury is unique among metals as it remains in the liquid state at 298 K. Thus, its standard state at this temperature is a liquid.
05

Determine Standard State for Methane ( CH4 )

Methane is commonly found in its gaseous form at 298 K. Therefore, the standard state for methane is as a gas due to its low boiling point compared to room temperature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Substances at Standard State
Understanding the properties of substances in their standard state is crucial for both theoretical and practical chemistry. The standard state serves as a baseline to compare different chemical substances and reactions. This helps chemists understand how substances behave under a standardized set of conditions.
When we talk about a substance's properties in its standard state, we often refer to:
  • Physical State: Is the substance a solid, liquid, or gas at 298 K?
  • Standard Enthalpy: The heat content of a substance in its standard state.
  • Standard Entropy: The disorder or randomness in a substance's standard state.
  • Standard Gibbs Free Energy: Determines the spontaneity of a substance's reaction under standard conditions.
These properties allow scientists to predict and calculate how reactions will proceed and how substances will interact, providing a consistent framework for experiments and industrial applications.
Standard Conditions for Chemical Substances
In chemistry, 'standard conditions' refer to a well-defined set of environmental parameters. These conditions provide a consistent basis to measure and report the properties of chemical substances. The standard conditions are considered as:
  • Pressure: 1 bar (approximately 1 atmosphere). This is used for measuring gas pressure and affects gas properties and reactions.
  • Temperature: 298 K (25°C). This temperature is commonly adopted because it represents room temperature in many academic and laboratory settings.
By having these constant conditions, it enables chemists to have a universal frame of reference for studying and comparing the properties and behaviors of substances worldwide. It ensures consistency across different reports, studies, and experiments.
Phase of Substances at 298 K
The phase of a substance at 298 K plays a significant role in determining its behavior and interaction in chemical reactions. At this temperature:
  • Water ( H_2O ): Exists as a liquid. Water remains in its liquid state due to the relatively high boiling point compared to 298 K.
  • Sodium Chloride ( NaCl ): Is solid. NaCl forms a characteristic crystalline structure at this temperature, known as table salt.
  • Mercury ( Hg ): Is liquid. Unique among metals, mercury retains its liquid form largely due to its low melting point.
  • Methane ( CH_4 ): Is gaseous. CHâ‚„ exists in a gaseous state at 298 K as its boiling point is significantly lower than this temperature.
The phase of these substances at 298 K indicates their normal state of existence within a given environmental condition, essential for accurate scientific calculations and practical industrial applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the lab, you plan to carry out a calorimetry experiment to determine \(\Delta_{r} H\) for the exothermic reaction of \(\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s})\) and \(\mathrm{HCl}(\mathrm{aq}) .\) Predict how each of the following will affect the calculated value of \(\Delta_{t} H .\) (The value calculated for \(\Delta_{i} H\) for this reaction is a negative value so choose your answer from the following: \(\Delta, H\) will be too low [that is, a larger negative valuel, \(\Delta_{r} H\) will be unaffected, \(\Delta_{r} H\) will be too high [that is, a smaller negative value].) (a) You spill a little bit of the \(\mathrm{Ca}(\mathrm{OH})_{2}\) on the benchtop before adding it to the calorimeter. (b) Because of a miscalculation, you add an excess of HCl to the measured amount of \(\mathrm{Ca}(\mathrm{OH})_{2}\) in the calorimeter. (c) \(\mathrm{Ca}(\mathrm{OH})_{2}\) readily absorbs water from the air. The \(\mathrm{Ca}(\mathrm{OH})_{2}\) sample you weighed had been exposed to the air prior to weighing and had absorbed some water. (d) After weighing out \(\mathrm{Ca}(\mathrm{OH})_{2},\) the sample sat in an open beaker and absorbed water. (e) You delay too long in recording the final temperature. (f) The insulation in your coffee-cup calorimeter was poor, so some energy as heat was lost to the surroundings during the experiment. (g) You have ignored the fact that energy as heat also raised the temperature of the stirrer and the thermometer in your system.

Chloromethane, \(\mathrm{CH}_{3} \mathrm{Cl},\) arises from microbial fermentation and is found throughout the environment. It is also produced industrially, is used in the manufacture of various chemicals, and has been used as a topical anesthetic. How much energy is required to convert \(92.5 \mathrm{g}\) of liquid to a vapor at its boiling point, \(-24.09^{\circ} \mathrm{C} ?\) (The heat of vaporization of \(\mathrm{CH}_{3} \mathrm{Cl}\) is \(21.40 \mathrm{kJ} / \mathrm{mol} .\) )

Energy: Some Basic Principles Define the terms system and surroundings. What does it mean to say that a system and its surroundings are in thermal equilibrium?

The value of \(\Delta U\) for the decomposition of \(7.647 \mathrm{g}\) of ammonium nitrate can be measured in a bomb calorimeter. The reaction that occurs is \\[ \mathrm{NH}_{4} \mathrm{NO}_{3}(\mathrm{s}) \rightarrow \mathrm{N}_{2} \mathrm{O}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\] The temperature of the calorimeter, which contains \(415 \mathrm{g}\) of water, increases from \(18.90^{\circ} \mathrm{C}\) to \(20.72^{\circ} \mathrm{C}\) The heat capacity of the bomb is \(155 \mathrm{J} / \mathrm{K}\). What is the value of \(\Delta U\) for this reaction, in \(\mathrm{kJ} / \mathrm{mol}\) ? (IMAGE CANNOT COPY)

When 108 g of water at a temperature of \(22.5^{\circ} \mathrm{C}\) is mixed with \(65.1 \mathrm{g}\) of water at an unknown temperature, the final temperature of the resulting mixture is \(47.9^{\circ} \mathrm{C}\). What was the initial temperature of the second sample of water?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.