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What mass of oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},\) is required to prepare \(250 .\) mL of a solution that has a concentration of \(0.15 \mathrm{M} \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} ?\)

Short Answer

Expert verified
3.38 g of oxalic acid is needed.

Step by step solution

01

Understand the Problem

We need to find the mass of oxalic acid (\(\text{H}_2\text{C}_2\text{O}_4\)) needed to make a solution with a given concentration and volume. The concentration, or molarity, is \(0.15 \, \text{M}\), and the volume of the solution is \(250 \, \text{mL}\).
02

Convert Volume to Liters

Since molarity is in moles per liter, we need the volume in liters. Convert \(250 \, \text{mL}\) to liters: \[250 \, \text{mL} = 0.250 \, \text{L}\].
03

Calculate Moles of Oxalic Acid Needed

Use the formula \(M = \frac{n}{V}\) to find the moles of oxalic acid needed.\[0.15 \, \text{M} = \frac{n}{0.250 \, \text{L}} \\Rightarrow n = 0.15 \times 0.250 = 0.0375 \, \text{mol}\]
04

Calculate Mass from Moles

Find the molar mass of oxalic acid: \(\text{H}_2\text{C}_2\text{O}_4\)= \((2 \times 1.01) + (2 \times 12.01) + (4 \times 16.00) = 90.03 \, \text{g/mol}\). Use the molar mass to convert moles to grams: \[0.0375 \, \text{mol} \times 90.03 \, \text{g/mol} = 3.376125 \, \text{g}\].
05

Round to Appropriate Significant Figures

The given concentration (\(0.15 \, \text{M}\)) has two significant figures, so round the mass of oxalic acid to two significant figures: \[3.38 \, \text{g}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity
Molarity is all about measuring concentration. Essentially, it tells us how much solute is present in a solution. This is very helpful in chemistry when you need to mix solutions precisely. Molarity is defined as the number of moles of solute divided by the volume of the solution in liters. The formula is:
  • \[ M = \frac{n}{V} \]
Here, \(M\) stands for molarity, \(n\) is the number of moles, and \(V\) is the volume of the solution in liters. This concept allows scientists to compare the concentrations of different solutions easily.
When working with solutions, it's crucial to convert measurements to the correct units—especially volume into liters. Remember, 1 liter is equal to 1000 milliliters. For example, if you have 250 ml, converting it to liters will give you 0.250 L. This conversion step is foundational for calculating molarity and ensuring accuracy in your work.
Moles to Grams Conversion
Converting moles to grams involves using the molar mass, which is a measure of a compound's mass per mole. This is important for determining the actual amount of a substance you have in your sample or, conversely, how much you need to make a solution. The conversion formula is:
  • \[ ext{grams} = ext{moles} imes ext{molar mass} \]
The molar mass can be found on the periodic table and is expressed in grams per mole (g/mol). It's calculated by adding up the atomic masses of all the atoms in a molecule. Take oxalic acid (\(\text{H}_2\text{C}_2\text{O}_4\)) as an example. You find the molar mass by summing the masses of all its atoms:
  • 2 hydrogen atoms: \(2 \times 1.01\)
  • 2 carbon atoms: \(2 \times 12.01\)
  • 4 oxygen atoms: \(4 \times 16.00\)
After summing these, you get a total molar mass of 90.03 g/mol. Once you have the moles of oxalic acid, multiplying by this molar mass gives you the desired grams.
Oxalic Acid
Oxalic acid is a simple, organic compound with the formula \(\text{H}_2\text{C}_2\text{O}_4\). It occurs naturally in many plants and vegetables, such as rhubarb. Chemically, it is also known for its ability to act as a reducing agent in chemical reactions.
In lab scenarios, oxalic acid is often used to prepare specific concentrations in solutions because it is a well-defined compound with predictable reactions. This compound is also crucial in titration processes as it can help determine the concentration of unknown solutions. It plays a significant role when it comes to neutralizing bases in chemical reactions as well. Understanding its properties and behavior in various environments allows chemists to use it effectively in experiments and manufacturing processes.
Moreover, when creating a solution from a solid, oxalic acid's clearly defined molar mass allows for precise calculations. This makes the preparation of solutions with known molarity using oxalic acid straightforward and efficient.

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Most popular questions from this chapter

Vitamin C has the formula \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}\). Besides being an acid, it is a reducing agent. One method for determining the amount of vitamin \(\mathrm{C}\) in a sample is to titrate it with a solution of bromine, \(\mathrm{Br}_{2}\), an oxidizing agent. $$\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}(\mathrm{aq})+\mathrm{Br}_{2}(\mathrm{aq}) \rightarrow 2 \mathrm{HBr}(\mathrm{aq})+\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}(\mathrm{aq})$$ A 1.00 -g "chewable" vitamin C tablet requires \(27.85 \mathrm{mL}\) of \(0.102 \mathrm{M} \mathrm{Br}_{2}\) for titration to the equivalence point. What is the mass of vitamin \(\mathrm{C}\) in the tablet?

Chromium(III) chloride forms many compounds with ammonia. To find the formula of one of these compounds, you titrate the \(\mathrm{NH}_{3}\) in the compound with standardized acid. $$\begin{array}{rl}\operatorname{Cr}\left(\mathrm{NH}_{3}\right)_{x} \mathrm{Cl}_{3}(\mathrm{aq})+ & x \mathrm{HCl}(\mathrm{aq}) \rightarrow \\\x & \mathrm{NH}_{4}^{+}(\mathrm{aq})+\mathrm{Cr}^{3+}(\mathrm{aq})+(x+3) \mathrm{Cl}^{-}(\mathrm{aq})\end{array}$$ Assume that \(24.26 \mathrm{mL}\) of \(1.500 \mathrm{M} \mathrm{HCl}\) is used to titrate \(1.580 \mathrm{g}\) of \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{x} \mathrm{Cl}_{3} .\) What is the value of \(x ?\)

Menthol, from oil of mint, has a characteristic odor. The compound contains only \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O}\) If \(95.6 \mathrm{mg}\) of menthol burns completely in \(\mathrm{O}_{2}\) and gives \(269 \mathrm{mg}\) of \(\mathrm{CO}_{2}\) and \(111 \mathrm{mg}\) of \(\mathrm{H}_{2} \mathrm{O}\) what is the empirical formula of menthol?

Titanium(IV) oxide, \(\mathrm{TiO}_{2}\), is heated in hydrogen gas to give water and a new titanium oxide, \(\mathrm{Ti}_{x} \mathrm{O}_{y},\) If \(1.598 \mathrm{g}\) of \(\mathrm{TiO}_{2}\) produces \(1.438 \mathrm{g}\) of \(\mathrm{Ti}_{x} \mathrm{O}_{y},\) what is the empirical formula of the new oxide?

An Alka-Seltzer tablet contains exactly \(100 . \mathrm{mg}\) of citric acid, \(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7},\) plus some sodium bicarbonate. What mass of sodium bicarbonate is required to consume \(100 .\) mg of citric acid by the following reaction? $$\begin{aligned}\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(\mathrm{aq})+3 \mathrm{NaHCO}_{3}(\mathrm{aq}) \rightarrow & \\\3 \mathrm{H}_{2} \mathrm{O}(\ell)+3 \mathrm{CO}_{2}(\mathrm{g}) &+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(\mathrm{aq})\end{aligned}$$

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