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Calculate the binding energy per mole of nucleons for \(_{8}^{16} \mathrm{O} .\) Masses needed for this calculation are \(_{1}^{1} \mathrm{H}=1.00783,_{0}^{1} \mathrm{n}=1.00867,\) and \(_{8}^{16} \mathrm{O}=15.99492\)

Short Answer

Expert verified
The binding energy per nucleon for \\(_{8}^{16}\text{O}\\) is 7.70 MeV.

Step by step solution

01

Calculate the Total Mass of Protons and Neutrons

To start, calculate the total mass of the protons and neutrons in one oxygen nucleus. Oxygen \(_{8}^{16}\)\(\text{O}\) contains 8 protons and 8 neutrons. The total mass is given by: \[ 8 \times ext{Mass of proton} + 8 \times ext{Mass of neutron} = 8 \times 1.00783 + 8 \times 1.00867 = 16.1272 \text{ u} \]
02

Calculate the Mass Defect

Next, find the mass defect, \(\Delta m\), by subtracting the actual mass of the oxygen nucleus from the calculated total mass of its protons and neutrons. \[ \Delta m = (16.1272 - 15.99492) \text{ u} = 0.13228 \text{ u} \]
03

Convert Mass Defect to Energy

Convert the mass defect to energy using Einstein's mass-energy equivalence formula, \( E = \Delta m \cdot c^2 \). Since \( c = 3.00 \times 10^8 \text{ m/s} \) and \( 1 \text{ u} = 931.5 \text{ MeV/c}^2 \): \[ E = 0.13228 \text{ u} \times 931.5 \text{ MeV/u} = 123.21 \text{ MeV} \] The energy calculated here is for one nucleus of oxygen.
04

Calculate Binding Energy per Nucleon

The total number of nucleons (protons and neutrons) in an oxygen nucleus is 16. To find the binding energy per nucleon:\[ \text{Binding energy per nucleon} = \frac{123.21 \text{ MeV}}{16} = 7.70 \text{ MeV} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Defect
In the realm of nuclear physics, the concept of mass defect plays a pivotal role in understanding the stability of an atom's nucleus. The mass defect refers to the discrepancy between the calculated total mass of an atom's protons and neutrons and the actual measured mass of the atom. This difference arises because some of the mass is converted into binding energy, which holds the nucleus together.
For example, in the case of the oxygen-16 nucleus, we first calculate the total mass of the nucleons, which includes 8 protons and 8 neutrons. The resulting calculated mass is 16.1272 atomic mass units (u). Yet, the measured mass of the oxygen nucleus is only 15.99492 u.
The mass defect, \( \Delta m \), is then \( 16.1272 \, \text{u} - 15.99492 \, \text{u} = 0.13228 \, \text{u} \). This seemingly missing mass instead manifests as the energy required to bind the nucleons within the nucleus, underscoring the profound relationship between mass and energy in nuclear reactions.
Einstein's Mass-Energy Equivalence
A cornerstone of modern physics, Einstein's mass-energy equivalence, is eloquently expressed in the equation \( E = mc^2 \). This formula reveals one of the universe’s wonders: mass and energy are interchangeable and can convert into each other.
In nuclear physics, this principle explains how the mass defect translates into binding energy. Using the calculated mass defect from the oxygen-16 nucleus, we can determine how much energy is equivalent to this 'lost' mass. By multiplying the mass defect in atomic mass units with \( 931.5 \, \text{MeV/u} \), we obtain the equivalent energy.
For the oxygen-16 nucleus, applying \( E = \Delta m \, c^2 = 0.13228 \, \text{u} \times 931.5 \, \text{MeV/u} = 123.21 \, \text{MeV} \), gives us the energy that binds the nucleus together. This calculation shows how intricately mass and energy are linked at the atomic level.
Oxygen-16 Nucleus
The oxygen-16 nucleus is a specific isotope of the element oxygen and is commonly represented by the symbol \( _{8}^{16} \text{O} \). Within its nucleus, it houses 8 protons and 8 neutrons, making a total of 16 nucleons.
Oxygen-16 is a fundamental part of many chemical processes and plays a significant role in biological systems and the earth's atmosphere. In nuclear physics, scripts like the mass defect and binding energy depend heavily on understanding the structure of such nuclei.
The binding energy of the oxygen-16 nucleus provides insights into the stability of the nucleus. Calculating how much energy would be required to disassemble the nucleus into individual protons and neutrons shows us how strong the nuclear forces are that hold it together. In the case of oxygen-16, the calculated total binding energy becomes evident in the calculations from its nucleons, showing a high level of stability which is common among elements with equal numbers of protons and neutrons.
Nucleons
In nuclear physics, the term nucleons refers to the composite particles protons and neutrons residing within an atomic nucleus. The behavior and configuration of nucleons determine much about the chemical and physical properties of an element.
  • Protons have a positive charge and define the atomic number of an element, fundamentally determining the element's identity.
  • Neutrons, however, have no charge but contribute to the mass and stability of a nucleus.
The total number of nucleons in a nucleus is called the mass number. For oxygen-16, the mass number is 16, comprised of 8 protons and 8 neutrons.
Calculating properties like the binding energy per nucleon is essential to understanding the energy efficiency of nuclear reactions. We derive this by dividing the total binding energy by the number of nucleons. For oxygen-16, the binding energy per nucleon is 7.70 MeV, indicating how tightly each nucleon is held within the nucleus.

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Most popular questions from this chapter

Iodine-131 \(\left(t_{1 / 2}=8.04 \text { days }\right),\) a \(\beta\) emitter, is used to treat thyroid cancer. (a) Write an equation for the decomposition of \(^{131}\) I. (b) If you ingest a sample of NaI containing \(^{131}\) I, how much time is required for the activity to decrease to \(35.0 \%\) of its original value?

To measure the volume of the blood system of an animal, the following experiment was done. A \(1.0-\mathrm{mL}\) sample of an aqueous solution containing tritium, with an activity of \(2.0 \times 10^{6} \mathrm{dps},\) was injected into the animal's bloodstream. After time was allowed for complete circulatory mixing, a \(1.0-\mathrm{mL}\) blood sample was withdrawn and found to have an activity of \(1.5 \times 10^{4}\) dps. What was the volume of the circulatory system? (The half-life of tritium is 12.3 years, so this experiment assumes that only a negligible amount of tritium has decayed in the time of the experiment.)

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